JEE Challenger
More from p-Block Elements (Group 15-18)

Precipitate Reaction of Hydrogen Halides with Silver Nitrate and Sodium Thiosulfate

Which of the specified hydrogen halides react with AgNO3(aq)\text{AgNO}_3(\text{aq}) to form a precipitate that dissolves in Na2S2O3(aq)\text{Na}_2\text{S}_2\text{O}_3(\text{aq})?

Options

A

HCl\text{HCl}

Correct
B

HF\text{HF}

C

HBr\text{HBr}

Correct
D

HI\text{HI}

Correct

Step-by-Step Solution

To determine which hydrogen halides react with aqueous silver nitrate (AgNO3\text{AgNO}_3) to give a precipitate that dissolves in aqueous sodium thiosulfate (Na2S2O3\text{Na}_2\text{S}_2\text{O}_3), we analyze the behavior of each hydrogen halide (HX\text{HX}):

  1. Reaction with Aqueous AgNO3\text{AgNO}_3:

    • HF\text{HF} (Option B): HF(aq)+AgNO3(aq)→AgF(aq)+HNO3(aq)\text{HF}(\text{aq}) + \text{AgNO}_3(\text{aq}) \rightarrow \text{AgF}(\text{aq}) + \text{HNO}_3(\text{aq}) Silver fluoride (AgF\text{AgF}) is highly soluble in water due to the high hydration energy of the fluoride ion (F−\text{F}^-). Therefore, no precipitate is formed.

    • HCl\text{HCl} (Option A): HCl(aq)+AgNO3(aq)→AgCl(s)↓+HNO3(aq)\text{HCl}(\text{aq}) + \text{AgNO}_3(\text{aq}) \rightarrow \text{AgCl}(\text{s})\downarrow + \text{HNO}_3(\text{aq}) A white precipitate of silver chloride (AgCl\text{AgCl}) is formed.

    • HBr\text{HBr} (Option C): HBr(aq)+AgNO3(aq)→AgBr(s)↓+HNO3(aq)\text{HBr}(\text{aq}) + \text{AgNO}_3(\text{aq}) \rightarrow \text{AgBr}(\text{s})\downarrow + \text{HNO}_3(\text{aq}) A pale yellow precipitate of silver bromide (AgBr\text{AgBr}) is formed.

    • HI\text{HI} (Option D): HI(aq)+AgNO3(aq)→AgI(s)↓+HNO3(aq)\text{HI}(\text{aq}) + \text{AgNO}_3(\text{aq}) \rightarrow \text{AgI}(\text{s})\downarrow + \text{HNO}_3(\text{aq}) A yellow precipitate of silver iodide (AgI\text{AgI}) is formed.

  2. Dissolution of Precipitates in Aqueous Na2S2O3\text{Na}_2\text{S}_2\text{O}_3: The silver halide precipitates (AgCl\text{AgCl}, AgBr\text{AgBr}, and AgI\text{AgI}) react with sodium thiosulfate to form a soluble complex, sodium dithiosulphatoargentate(I):

    AgX(s)+2Na2S2O3(aq)→Na3[Ag(S2O3)2](aq)+NaX(aq)(where X=Cl,Br,I)\text{AgX}(\text{s}) + 2\text{Na}_2\text{S}_2\text{O}_3(\text{aq}) \rightarrow \text{Na}_3[\text{Ag}(\text{S}_2\text{O}_3)_2](\text{aq}) + \text{NaX}(\text{aq}) \quad (\text{where } \text{X} = \text{Cl}, \text{Br}, \text{I})

    Because the formation constant (KfK_f) of the complex [Ag(S2O3)2]3−[\text{Ag}(\text{S}_2\text{O}_3)_2]^{3-} is extremely high, even the least soluble silver halide, AgI\text{AgI}, dissolves in aqueous Na2S2O3\text{Na}_2\text{S}_2\text{O}_3.

Thus, HCl\text{HCl}, HBr\text{HBr}, and HI\text{HI} form precipitates with AgNO3(aq)\text{AgNO}_3(\text{aq}) that subsequently dissolve in Na2S2O3(aq)\text{Na}_2\text{S}_2\text{O}_3(\text{aq}).

Correct Options: (A), (C), and (D)