JEE Challenger
More from d and f Block Elements

Identification of Chemical Reagent S

Identify the formula corresponding to reagent S\mathbf{S}:

Options

A

K4[Fe(CN)6]\mathrm{K}_4[\mathrm{Fe}(\mathrm{CN})_6]

B

Na2HPO4\mathrm{Na}_2\mathrm{HPO}_4

C

K2CrO4\mathrm{K}_2\mathrm{CrO}_4

D

KOH\mathrm{KOH}

Correct

Step-by-Step Solution

Based on the comprehensive scheme of qualitative analysis from this passage (JEE Advanced 2014):

  1. Analysis of the Passage Scheme: The paragraph presents a flow-chart involving reactions of metal cations with various specific qualitative inorganic reagents, designated as P\mathbf{P}, Q\mathbf{Q}, R\mathbf{R}, and S\mathbf{S}.

  2. Reactions and Identification:

    • Metal ions such as Pb2+\mathrm{Pb}^{2+}, Zn2+\mathrm{Zn}^{2+}, or amphoteric cations precipitate as hydroxides when treated with a strong base and dissolve in an excess of the reagent to form soluble tetrahydroxo-complexes (e.g., tetrahydroxozincate(II) or tetrahydroxoplumbate(II)): M2++2OH−⟶M(OH)2↓\mathrm{M}^{2+} + 2\mathrm{OH}^- \longrightarrow \mathrm{M(OH)}_2 \downarrow M(OH)2+2OH−⟶[M(OH)4]2−\mathrm{M(OH)}_2 + 2\mathrm{OH}^- \longrightarrow [\mathrm{M(OH)}_4]^{2-}
    • This amphoteric behavior—forming a white precipitate that dissolves in an excess of the reagent to yield a clear, colorless solution—unambiguously identifies reagent S\mathbf{S} as a strong base, potassium hydroxide (KOH\mathrm{KOH}).
  3. Conclusion: Reagent S\mathbf{S} is KOH\mathrm{KOH}.

Therefore, the correct option is (D).