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Calculate Pressure Difference at Chimney Cap

Comprehension Passage

A cylindrical furnace has height (HH) and diameter (DD) both 1 m1\text{ m}. It is maintained at temperature 360 K360\text{ K}. The air gets heated inside the furnace at constant pressure PaP_a and its temperature becomes T=360 KT = 360\text{ K}. The hot air with density ρ\rho rises up a vertical chimney of diameter d=0.1 md = 0.1\text{ m} and height h=9 mh = 9\text{ m} above the furnace and exits the chimney (see the figure). As a result, atmospheric air of density ρa=1.2 kg m3\rho_a = 1.2\text{ kg m}^{-3}, pressure PaP_a and temperature Ta=300 KT_a = 300\text{ K} enters the furnace. Assume air as an ideal gas, neglect the variations in ρ\rho and TT inside the chimney and the furnace. Also ignore the viscous effects.

[Given: The acceleration due to gravity g=10 m s2g = 10\text{ m s}^{-2} and π=3.14\pi = 3.14]

When the chimney is closed using a cap at the top, a pressure difference ΔP\Delta P develops between the top and the bottom surfaces of the cap. If the changes in the temperature and density of the hot air, due to the stoppage of air flow, are negligible then the value of ΔP\Delta P is ______ N m2\text{N m}^{-2}.

Question Diagram 1
Official Numerical Answer20

Step-by-Step Solution

To find the pressure difference ΔP\Delta P between the top and bottom surfaces of the cap when the chimney is closed, we proceed step-by-step:

1. Density of the Hot Air (ρ\rho)

Assuming air behaves as an ideal gas, the pressure, density, and temperature are related by P=ρRTMP = \frac{\rho R T}{M}.

Since the air enters the furnace at pressure PaP_a and stays at constant pressure inside the furnace: ρT=ρaTa\rho T = \rho_a T_a

Substituting the given values (ρa=1.2 kg m3\rho_a = 1.2 \text{ kg m}^{-3}, Ta=300 KT_a = 300 \text{ K}, and T=360 KT = 360 \text{ K}): ρ=ρa(TaT)=1.2×300360=1.0 kg m3\rho = \rho_a \left(\frac{T_a}{T}\right) = 1.2 \times \frac{300}{360} = 1.0 \text{ kg m}^{-3}


2. Pressure Distribution

Let z=0z = 0 correspond to the bottom of the furnace, where atmospheric air enters and the pressure both inside and outside is PaP_a.

The total height of the hot air column from the bottom of the furnace to the top of the chimney is: Htotal=H+h=1 m+9 m=10 mH_{\text{total}} = H + h = 1 \text{ m} + 9 \text{ m} = 10 \text{ m}

  • Outside Pressure at the top of the cap (PtopP_{\text{top}}): Due to the ambient air column of density ρa\rho_a: Ptop=Paρag(H+h)P_{\text{top}} = P_a - \rho_a g (H + h)

  • Inside Pressure at the bottom of the cap (PbottomP_{\text{bottom}}): Due to the hot air column of density ρ\rho: Pbottom=Paρg(H+h)P_{\text{bottom}} = P_a - \rho g (H + h)


3. Calculation of Pressure Difference (ΔP\Delta P)

The pressure difference across the cap is: ΔP=PbottomPtop=(ρaρ)g(H+h)\Delta P = P_{\text{bottom}} - P_{\text{top}} = (\rho_a - \rho) g (H + h)

Substituting the values (g=10 m s2g = 10 \text{ m s}^{-2}): ΔP=(1.21.0)×10×10=0.2×100=20 N m2\Delta P = (1.2 - 1.0) \times 10 \times 10 = 0.2 \times 100 = 20 \text{ N m}^{-2}

Final Answer: The value of ΔP\Delta P is 20.