To find the value of the given expression, let the expression be denoted by E:
E=ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d)
Step 1: Use Vieta's formulas for both quadratic polynomials
For the quadratic equation x2+20x−2020=0, the roots are a and b. By Vieta's formulas:
a+b=−20
ab=−2020
For the quadratic equation x2−20x+2020=0, the roots are c and d. By Vieta's formulas:
c+d=20
cd=2020
Step 2: Simplify the expression E
Expand the given expression:
E=a2c−ac2+a2d−ad2+b2c−bc2+b2d−bd2
Grouping the terms with a2,b2 together and c2,d2 together:
E=a2(c+d)+b2(c+d)−c2(a+b)−d2(a+b)
E=(a2+b2)(c+d)−(c2+d2)(a+b)
Step 3: Calculate a2+b2 and c2+d2
Using the algebraic identity x2+y2=(x+y)2−2xy:
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For a2+b2:
a2+b2=(a+b)2−2ab
a2+b2=(−20)2−2(−2020)=400+4040=4440
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For c2+d2:
c2+d2=(c+d)2−2cd
c2+d2=(20)2−2(2020)=400−4040=−3640
Step 4: Substitute the values into the expression E
E=(4440)(20)−(−3640)(−20)
E=88800−72800=16000
Thus, the value of the expression is 16000.
Correct Option: (D)