JEE Challenger
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Transmitted and Reflected Intensity versus Angle of Incidence at Interface

A light ray traveling in glass medium is incident on glass-air interface at an angle of incidence θ\theta. The reflected ( R ) and transmitted ( T ) intensities, both as function of θ\theta, are plotted. The correct sketch is

Options

A
Option A Diagram 1
B
Option B Diagram 1
C
Option C Diagram 1
Correct
D
Option D Diagram 1

Step-by-Step Solution

When a light ray travels from a denser medium (glass with refractive index μ>1\mu > 1) to a rarer medium (air with refractive index μair=1\mu_{\text{air}} = 1), the reflection (RR) and transmission (TT) characteristics depend on the angle of incidence θ\theta relative to the critical angle θc=sin⁡−1(1μ)\theta_c = \sin^{-1}\left(\frac{1}{\mu}\right):

  1. At Normal Incidence (θ=0∘\theta = 0^\circ):

    • Using Fresnel's reflection formula at normal incidence:
      R(0)=(μ−1μ+1)2I0R(0) = \left(\frac{\mu - 1}{\mu + 1}\right)^2 I_0
      For typical glass (μ≈1.5\mu \approx 1.5), R(0)≈4%R(0) \approx 4\% and T(0)=I0−R(0)≈96%T(0) = I_0 - R(0) \approx 96\%.
  2. For Angles Below the Critical Angle (0<θ<θc0 < \theta < \theta_c):

    • As θ\theta increases towards the critical angle θc\theta_c, the angle of refraction rr approaches 90∘90^\circ.
    • The reflected intensity R(θ)R(\theta) increases monotonically and steeply approaches 100%100\% as θ→θc−\theta \to \theta_c^-.
    • Correspondingly, the transmitted intensity T(θ)=I0−R(θ)T(\theta) = I_0 - R(\theta) decreases monotonically to 0%0\% as θ→θc−\theta \to \theta_c^-.
  3. At and Beyond the Critical Angle (θ≥θc\theta \ge \theta_c):

    • Total Internal Reflection (TIR) occurs for all angles of incidence θ≥θc\theta \ge \theta_c.
    • Thus, for θc≤θ≤90∘\theta_c \le \theta \le 90^\circ:
      R(θ)=100%andT(θ)=0%R(\theta) = 100\% \quad \text{and} \quad T(\theta) = 0\%

Graph (C) correctly illustrates this behavior:

  • TT drops to 0%0\% at θ=θc\theta = \theta_c and remains zero up to 90∘90^\circ.
  • RR rises to 100%100\% at θ=θc\theta = \theta_c and remains at 100%100\% up to 90∘90^\circ.

Correct Option: (C)