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Speed of Whistle Sound Observed by Train Passengers

Comprehension Passage

Two trains AA and BB are moving with speeds 20 m/s20\text{ m/s} and 30 m/s30\text{ m/s} respectively in the same direction on the same straight track, with BB ahead of AA. The engines are at the front ends. The engine of train AA blows a long whistle.

Assume that the sound of the whistle is composed of components varying in frequency from f1=800 Hzf_1 = 800\text{ Hz} to f2=1120 Hzf_2 = 1120\text{ Hz}. The speed of sound in still air is 340 m/s340\text{ m/s}.

The speed of sound of the whistle is

Options

A

340 m/s340\text{ m/s} for passengers in A and 310 m/s310\text{ m/s} for passengers in B

B

360 m/s360\text{ m/s} for passengers in A and 310 m/s310\text{ m/s} for passengers in B

Correct
C

310 m/s310\text{ m/s} for passengers in A and 360 m/s360\text{ m/s} for passengers in B

D

340 m/s340\text{ m/s} for passengers in both the trains

Step-by-Step Solution

To find the speed of sound of the whistle observed by the passengers in trains AA and BB, we consider the relative velocity of sound with respect to the observers in each train.

1. Context and Given Parameters:

  • Train AA and train BB are moving in the same direction (let this be along the positive xx-axis, +i^+\hat{i}) on parallel tracks with speeds:
    vA=20 m/s,vB=30 m/sv_A = 20\text{ m/s}, \quad v_B = 30\text{ m/s}
  • Train AA is behind train BB.
  • The speed of sound in still air is v=340 m/sv = 340\text{ m/s}.

2. Relative Speed of Sound for Passengers in Train AA:

  • The sound waves reaching the passengers in train AA from the whistle travel in the backward direction (opposite to the direction of motion of the trains), so the velocity of sound in the air frame is:
    v⃗sound=−340 i^ m/s\vec{v}_{\text{sound}} = -340\,\hat{i}\text{ m/s}
  • The velocity of passengers in train AA is:
    v⃗A=20 i^ m/s\vec{v}_A = 20\,\hat{i}\text{ m/s}
  • The relative velocity of the sound wave with respect to the passengers in train AA is:
    v⃗sound,A=v⃗sound−v⃗A=−340 i^−20 i^=−360 i^ m/s\vec{v}_{\text{sound}, A} = \vec{v}_{\text{sound}} - \vec{v}_A = -340\,\hat{i} - 20\,\hat{i} = -360\,\hat{i}\text{ m/s}
  • Thus, the observed speed of sound for passengers in train AA is:
    ∣v⃗sound,A∣=360 m/s|\vec{v}_{\text{sound}, A}| = 360\text{ m/s}

3. Relative Speed of Sound for Passengers in Train BB:

  • For passengers in train BB, the whistle is on train BB and the sound traveling forward along the train moves in the direction of the train's motion, so:
    v⃗sound=340 i^ m/s\vec{v}_{\text{sound}} = 340\,\hat{i}\text{ m/s}
  • The velocity of passengers in train BB is:
    v⃗B=30 i^ m/s\vec{v}_B = 30\,\hat{i}\text{ m/s}
  • The relative velocity of the sound wave with respect to the passengers in train BB is:
    v⃗sound,B=v⃗sound−v⃗B=340 i^−30 i^=310 i^ m/s\vec{v}_{\text{sound}, B} = \vec{v}_{\text{sound}} - \vec{v}_B = 340\,\hat{i} - 30\,\hat{i} = 310\,\hat{i}\text{ m/s}
  • Thus, the observed speed of sound for passengers in train BB is:
    ∣v⃗sound,B∣=310 m/s|\vec{v}_{\text{sound}, B}| = 310\text{ m/s}

Therefore, the speed of sound of the whistle is 360 m/s360\text{ m/s} for passengers in train AA and 310 m/s310\text{ m/s} for passengers in train BB.

Correct Option: (B)