JEE Challenger
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Speed and Wavelength of Light in a Meta-Material

Identify the correct statement regarding the propagation of light in a meta-material:

Options

A

The speed of light inside the meta-material is v=c∣n∣v = c|n|

B

The speed of light inside the meta-material is v=c∣n∣v = \frac{c}{|n|}

Correct
C

The speed of light inside the meta-material is v=cv = c

D

The wavelength of light in the meta-material (λm\lambda_m) is given by λm=λair∣n∣\lambda_m = \lambda_{\text{air}}|n|, where λair\lambda_{\text{air}} represents the wavelength in air.

Step-by-Step Solution

For light propagating in any optical medium, including an engineered meta-material where the refractive index nn can be negative, the physical speed of propagation vv is a positive scalar quantity.

By definition, the refractive index nn relates the speed of light in vacuum cc to the phase velocity of light in the medium via: ∣n∣=cv|n| = \frac{c}{v}

Rearranging this expression for the speed of light vv in the meta-material gives: v=c∣n∣v = \frac{c}{|n|}

Furthermore, since the frequency of light ν\nu remains invariant when light transitions from air into the meta-material, the wavelength of light in the meta-material λm\lambda_m is related to its speed by: λm=vν=c∣n∣ν=λair∣n∣\lambda_m = \frac{v}{\nu} = \frac{c}{|n|\nu} = \frac{\lambda_{\text{air}}}{|n|} where λair=cν\lambda_{\text{air}} = \frac{c}{\nu} is the wavelength of light in air (or vacuum).

Analyzing the given choices:

  • Option (A) is incorrect because v=c∣n∣v = \frac{c}{|n|}, not c∣n∣c|n|.
  • Option (B) is correct because v=c∣n∣v = \frac{c}{|n|}.
  • Option (C) is incorrect because light changes speed in a medium where ∣n∣≠1|n| \neq 1.
  • Option (D) is incorrect because λm=λair∣n∣\lambda_m = \frac{\lambda_{\text{air}}}{|n|}, not λair∣n∣\lambda_{\text{air}}|n|.

Therefore, the correct statement is given by option B.