JEE Challenger
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Reaction Pathways Leading to Ortho Xylene as Primary Product

Which of the following reaction sequence(s) result in oo-xylene as the predominant product?

Options

A
Option A
Correct
B
Option B
Correct
C
Option C
D
Option D

Step-by-Step Solution

To determine which reaction sequence(s) result in oo-xylene (1,2-dimethylbenzene) as the major product, we analyze each sequence at a high level:

  1. Option (A): Diazotization of oo-toluidine followed by reaction with CuCN\text{CuCN} yields oo-tolunitrile. Partial reduction of the nitrile using DIBAL-H\text{DIBAL-H} followed by hydrolysis gives oo-tolualdehyde. Subsequent Wolff-Kishner reduction (N2H4,KOH,Δ\text{N}_2\text{H}_4, \text{KOH}, \Delta) reduces the aldehyde group to a methyl group, yielding oo-xylene.

  2. Option (B): Formation of the Grignard reagent from oo-bromotoluene followed by carboxylation with CO2\text{CO}_2 yields oo-toluic acid. Conversion to the acyl chloride using SOCl2\text{SOCl}_2 followed by Rosenmund reduction (H2,Pd-BaSO4\text{H}_2, \text{Pd-BaSO}_4) yields oo-tolualdehyde. Finally, Clemmensen reduction (Zn-Hg, HCl\text{Zn-Hg, HCl}) converts the formyl group to a methyl group, yielding oo-xylene.

  3. Option (C): Hydroboration-oxidation of oo-methylstyrene yields 2−(o-tolyl)ethanol2-(o\text{-tolyl})ethanol. Conversion to the alkyl bromide using PBr3\text{PBr}_3 followed by reduction with Zn/dil. HCl\text{Zn/dil. HCl} converts the side chain into an ethyl group, resulting in oo-ethyltoluene instead of oo-xylene.

  4. Option (D): Reductive ozonolysis of the bicyclic alkene cleaves the non-aromatic double bond to form a dialdehyde derivative attached to the ring system, which upon Wolff-Kishner reduction does not yield oo-xylene.

Therefore, only reaction sequences (A) and (B) lead to oo-xylene as the major product.

Correct Options: (A), (B)