Properties and Structure of Ozone Molecule
Identify the correct statement(s) regarding ozone ():
Options
ACorrect
Both bond lengths are equal.
B
Thermal decomposition of is an endothermic process.
CCorrect
is diamagnetic in nature.
DCorrect
possesses a bent structure.
Topics & Concepts
Step-by-Step Solution
To determine the correct statements regarding the ozone () molecule, we analyze each statement individually:
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Structure and Bond Lengths (Statements A and D):
- The central oxygen atom in the molecule has a total of 6 valence electrons. In its Lewis structure, it forms a double bond with one terminal oxygen atom and a coordinate (dative/single) bond with the other terminal oxygen atom, retaining one lone pair of electrons:
- The steric number of the central oxygen atom is: This corresponds to hybridization with a trigonal planar electron-pair geometry. Because of the presence of the lone pair, the molecular geometry is bent (angular or V-shaped), with a bond angle of approximately . Thus, statement (D) is correct.
- Due to resonance, the two bonds are equivalent, resulting in a partial double-bond character (bond order of ) for both bonds. As a result, both bond lengths are identical and equal to approximately , intermediate between a single bond () and a double bond (). Thus, statement (A) is correct.
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Thermodynamics of Thermal Decomposition (Statement B):
- The decomposition of ozone into dioxygen is represented by:
- Ozone is thermodynamically less stable than molecular oxygen. Its standard enthalpy of formation from oxygen is positive ().
- Consequently, the decomposition of ozone to oxygen is an exothermic process (). This enthalpy change, combined with the increase in entropy ( as 2 moles of gas yield 3 moles of gas), results in a large negative Gibbs free energy change (), making the decomposition spontaneous and strongly exothermic. Thus, statement (B) is incorrect.
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Magnetic Nature (Statement C):
- The total number of electrons in an molecule is (including 18 valence electrons).
- In its ground electronic state, all electrons are paired across bonding, non-bonding, and molecular orbitals, leaving no unpaired electrons. Therefore, is diamagnetic. Thus, statement (C) is correct.
Hence, the correct statements are A, C, and D.