JEE Challenger
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Organic Compounds Giving Positive Tollens Test

A positive Tollen's test is given by which of the following compound(s)?

Options

A
Option A
Correct
B
Option B
Correct
C
Option C
Correct
D
Option D

Step-by-Step Solution

To determine which of the given compounds give a positive Tollens' test, we analyze the reactivity of each compound towards Tollens' reagent (ammoniacal silver nitrate solution, [Ag(NH3)2]+OH−[\text{Ag}(\text{NH}_3)_2]^+\text{OH}^-):

  1. Option (A): Propenal (CH2=CH−CHO\text{CH}_2=\text{CH}-\text{CHO}) Propenal is an aliphatic aldehyde. All aldehydes (aliphatic and aromatic) readily reduce Tollens' reagent to metallic silver, forming a silver mirror: CH2=CH−CHO+2[Ag(NH3)2]++3OH−⟶CH2=CH−COO−+2Ag↓+4NH3+2H2O\text{CH}_2=\text{CH}-\text{CHO} + 2[\text{Ag}(\text{NH}_3)_2]^+ + 3\text{OH}^- \longrightarrow \text{CH}_2=\text{CH}-\text{COO}^- + 2\text{Ag}\downarrow + 4\text{NH}_3 + 2\text{H}_2\text{O} Therefore, (A) gives a positive Tollens' test.

  2. Option (B): Benzaldehyde (C6H5CHO\text{C}_6\text{H}_5\text{CHO}) Benzaldehyde is an aromatic aldehyde. Like aliphatic aldehydes, it reduces Tollens' reagent to metallic silver: C6H5CHO+2[Ag(NH3)2]++3OH−⟶C6H5COO−+2Ag↓+4NH3+2H2O\text{C}_6\text{H}_5\text{CHO} + 2[\text{Ag}(\text{NH}_3)_2]^+ + 3\text{OH}^- \longrightarrow \text{C}_6\text{H}_5\text{COO}^- + 2\text{Ag}\downarrow + 4\text{NH}_3 + 2\text{H}_2\text{O} Therefore, (B) gives a positive Tollens' test.

  3. Option (C): Benzoin (Ph−CH(OH)−C(=O)−Ph\text{Ph}-\text{CH(OH)}-\text{C}(=\text{O})-\text{Ph}) Benzoin is an α\alpha-hydroxy ketone. Under the alkaline conditions of Tollens' reagent, α\alpha-hydroxy ketones tautomerize through an enediol intermediate and undergo oxidation to 1,2-diketones (benzil), reducing Ag+\text{Ag}^+ ions to metallic silver: Ph−CH(OH)−C(=O)−Ph+2[Ag(NH3)2]++2OH−⟶Ph−C(=O)−C(=O)−Ph+2Ag↓+4NH3+2H2O\text{Ph}-\text{CH(OH)}-\text{C}(=\text{O})-\text{Ph} + 2[\text{Ag}(\text{NH}_3)_2]^+ + 2\text{OH}^- \longrightarrow \text{Ph}-\text{C}(=\text{O})-\text{C}(=\text{O})-\text{Ph} + 2\text{Ag}\downarrow + 4\text{NH}_3 + 2\text{H}_2\text{O} Therefore, (C) gives a positive Tollens' test.

  4. Option (D): Chalcone (Ph−CH=CH−C(=O)−Ph\text{Ph}-\text{CH}=\text{CH}-\text{C}(=\text{O})-\text{Ph}) Chalcone is an α,β\alpha,\beta-unsaturated ketone. Simple ketones and α,β\alpha,\beta-unsaturated ketones do not possess the easily oxidizable aldehyde functional group or an α\alpha-hydroxy ketone moiety; hence, they do not reduce Tollens' reagent. Therefore, (D) does not give a positive Tollens' test.

Thus, the correct options are (A), (B), and (C).