JEE Challenger
More from p-Block Elements (Group 15-18)

Number of Compounds Reacting with Phosphorus Pentachloride to Yield Phosphoryl Chloride

Among the following, the nurnber of compounds than can react with PCl5\text{PCl}_5 to give POCl3\text{POCl}_3 is
O2\text{O}_2, CO2\text{CO}_2, SO2\text{SO}_2, H2O\text{H}_2\text{O}, H2SO4\text{H}_2\text{SO}_4, P4O10\text{P}_4\text{O}_{10}

Official Numerical Answer4

Step-by-Step Solution

To determine the number of compounds that can react with phosphorus pentachloride (PCl5\text{PCl}_5) to yield phosphoryl chloride (POCl3\text{POCl}_3), let us examine the reaction of PCl5\text{PCl}_5 with each of the given species:

  1. Reaction with O2\text{O}_2:
    Phosphorus in PCl5\text{PCl}_5 is already in its maximum oxidation state of +5+5. Hence, it cannot be oxidized further and does not react with O2\text{O}_2 to give POCl3\text{POCl}_3.
    PCl5+O2⟶No reaction\text{PCl}_5 + \text{O}_2 \longrightarrow \text{No reaction}

  2. Reaction with CO2\text{CO}_2:
    Carbon dioxide is thermodynamically very stable and an extremely weak oxygen-donor. It does not react with PCl5\text{PCl}_5.
    PCl5+CO2⟶No reaction\text{PCl}_5 + \text{CO}_2 \longrightarrow \text{No reaction}

  3. Reaction with SO2\text{SO}_2:
    Sulfur dioxide reacts with PCl5\text{PCl}_5 via oxygen-chlorine exchange to produce phosphoryl chloride and thionyl chloride:
    PCl5+SO2⟶POCl3+SOCl2\text{PCl}_5 + \text{SO}_2 \longrightarrow \text{POCl}_3 + \text{SOCl}_2

  4. Reaction with H2O\text{H}_2\text{O}:
    In limited water (or moist air), PCl5\text{PCl}_5 undergoes partial hydrolysis to produce phosphoryl chloride and hydrogen chloride:
    PCl5+H2O⟶POCl3+2HCl\text{PCl}_5 + \text{H}_2\text{O} \longrightarrow \text{POCl}_3 + 2\text{HCl}

  5. Reaction with H2SO4\text{H}_2\text{SO}_4:
    Sulfuric acid reacts with PCl5\text{PCl}_5 by replacing its hydroxyl groups with chlorine atoms, producing sulfuryl chloride (or chlorosulfuric acid) and POCl3\text{POCl}_3:
    H2SO4+2PCl5⟶SO2Cl2+2POCl3+2HCl\text{H}_2\text{SO}_4 + 2\text{PCl}_5 \longrightarrow \text{SO}_2\text{Cl}_2 + 2\text{POCl}_3 + 2\text{HCl}

  6. Reaction with P4O10\text{P}_4\text{O}_{10}:
    Phosphorus pentoxide reacts readily with PCl5\text{PCl}_5 upon heating to form POCl3\text{POCl}_3:
    6PCl5+P4O10⟶10POCl36\text{PCl}_5 + \text{P}_4\text{O}_{10} \longrightarrow 10\text{POCl}_3

Thus, the compounds that react with PCl5\text{PCl}_5 to give POCl3\text{POCl}_3 are SO2\text{SO}_2, H2O\text{H}_2\text{O}, H2SO4\text{H}_2\text{SO}_4, and P4O10\text{P}_4\text{O}_{10}.

The total number of such compounds is 4.