JEE Challenger
More from Polymers

Functional Group and Reagent Selection for Condensation Polymer Scheme

The correct functional group X\text{X} and the reagent/reaction conditions Y\text{Y} in the following scheme are

Diagram 0

Options

A

X=COOCH3\text{X} = \text{COOCH}_3 , Y=H2/Ni/heat\text{Y} = \text{H}_2/\text{Ni}/\text{heat}

B

X=CONH2\text{X} = \text{CONH}_2 , Y=H2/Ni/heat\text{Y} = \text{H}_2/\text{Ni}/\text{heat}

C

X=CONH2\text{X} = \text{CONH}_2 , Y=Br2/NaOH\text{Y} = \text{Br}_2/\text{NaOH}

Correct
D

X=CN\text{X} = \text{CN} , Y=H2/Ni/heat\text{Y} = \text{H}_2/\text{Ni}/\text{heat}

Correct

Step-by-Step Solution

To determine the correct functional group X\text{X} and reaction conditions Y\text{Y}, let us analyze the reaction sequence:

X−(CH2)4−X→(ii) HOOC−(CH2)4−COOH, Δ(i) YCondensation Polymer\text{X}-(\text{CH}_2)_4-\text{X} \xrightarrow[\text{(ii) } \text{HOOC}-(\text{CH}_2)_4-\text{COOH},\, \Delta]{\text{(i) } \text{Y}} \text{Condensation Polymer}

The reagent in the second step is adipic acid, HOOC−(CH2)4−COOH\text{HOOC}-(\text{CH}_2)_4-\text{COOH}, a dicarboxylic acid containing 66 carbon atoms. For condensation polymerization with a dicarboxylic acid, the intermediate compound produced after treatment with Y\text{Y} should typically be a bifunctional monomer such as a diamine or a diol. Specifically, reaction of diamines with dicarboxylic acids forms polyamides (nylons).

Let us evaluate the options:

  1. Analysis of Option (D):

    • Functional group: X=−CN\text{X} = -\text{CN}
    • The starting compound is adiponitrile (hexanedinitrile):
      NC−(CH2)4−CN\text{NC}-(\text{CH}_2)_4-\text{CN}
    • Treatment with Y=H2/Ni/heat\text{Y} = \text{H}_2/\text{Ni}/\text{heat} reduces the nitrile groups to primary amines:
      NC−(CH2)4−CN→H2/Ni/ΔH2N−(CH2)6−NH2(hexamethylenediamine)\text{NC}-(\text{CH}_2)_4-\text{CN} \xrightarrow{\text{H}_2/\text{Ni}/\Delta} \text{H}_2\text{N}-(\text{CH}_2)_6-\text{NH}_2 \quad (\text{hexamethylenediamine})
    • Subsequent reaction of hexamethylenediamine with adipic acid upon heating leads to the formation of the well-known condensation polymer Nylon-6,6:
      n H2N−(CH2)6−NH2+n HOOC−(CH2)4−COOH→Δ[NH−(CH2)6−NH−CO−(CH2)4−CO]n+2n H2On\,\text{H}_2\text{N}-(\text{CH}_2)_6-\text{NH}_2 + n\,\text{HOOC}-(\text{CH}_2)_4-\text{COOH} \xrightarrow{\Delta} \left[\text{NH}-(\text{CH}_2)_6-\text{NH}-\text{CO}-(\text{CH}_2)_4-\text{CO}\right]_n + 2n\,\text{H}_2\text{O}
    • Thus, option (D) is correct.
  2. Analysis of Option (C):

    • Functional group: X=−CONH2\text{X} = -\text{CONH}_2
    • The starting compound is adipamide:
      H2NOC−(CH2)4−CONH2\text{H}_2\text{NOC}-(\text{CH}_2)_4-\text{CONH}_2
    • Treatment with Y=Br2/NaOH\text{Y} = \text{Br}_2/\text{NaOH} causes the Hofmann bromamide degradation reaction. In this reaction, primary amides are converted to primary amines with the loss of the carbonyl carbon:
      H2NOC−(CH2)4−CONH2→Br2/NaOHH2N−(CH2)4−NH2(1,4-diaminobutane / tetramethylenediamine)\text{H}_2\text{NOC}-(\text{CH}_2)_4-\text{CONH}_2 \xrightarrow{\text{Br}_2/\text{NaOH}} \text{H}_2\text{N}-(\text{CH}_2)_4-\text{NH}_2 \quad (\text{1,4-diaminobutane / tetramethylenediamine})
    • Reaction of 1,4-diaminobutane with adipic acid on heating undergoes condensation polymerization to form Nylon-4,6:
      n H2N−(CH2)4−NH2+n HOOC−(CH2)4−COOH→Δ[NH−(CH2)4−NH−CO−(CH2)4−CO]n+2n H2On\,\text{H}_2\text{N}-(\text{CH}_2)_4-\text{NH}_2 + n\,\text{HOOC}-(\text{CH}_2)_4-\text{COOH} \xrightarrow{\Delta} \left[\text{NH}-(\text{CH}_2)_4-\text{NH}-\text{CO}-(\text{CH}_2)_4-\text{CO}\right]_n + 2n\,\text{H}_2\text{O}
    • Thus, option (C) is correct.
  3. Analysis of Options (A) and (B):

    • In (A), catalytic hydrogenation using H2/Ni/heat\text{H}_2/\text{Ni}/\text{heat} does not effectively reduce esters (X=−COOCH3\text{X} = -\text{COOCH}_3) to alcohols under standard laboratory conditions (esters generally require reagents such as LiAlH4\text{LiAlH}_4 or CuO⋅CuCr2O4\text{CuO}\cdot\text{CuCr}_2\text{O}_4 under extreme conditions).
    • In (B), catalytic hydrogenation of primary amides using H2/Ni\text{H}_2/\text{Ni} does not cleanly or primarily yield the corresponding amines.

Therefore, the correct options are (C) and (D).