JEE Challenger
More from p-Block Elements (Group 15-18)
ChemMedAdv 2009 • Paper 2

Matching Reactions of Copper and Zinc with Nitric Acid to Products

Match each of the reactions given in Column I with the corresponding product(s) given in Column II.

Column IColumn II(A) Cu+dil HNO3(p) NO(B) Cu+conc HNO3(q) NO2(C) Zn+dil HNO3(r) N2O(D) Zn+conc HNO3(s) Cu(NO3)2(t) Zn(NO3)2\begin{array}{ll} \textbf{Column I} & \textbf{Column II} \\ \text{(A) } \text{Cu} + \text{dil } \text{HNO}_3 & \text{(p) } \text{NO} \\ \text{(B) } \text{Cu} + \text{conc } \text{HNO}_3 & \text{(q) } \text{NO}_2 \\ \text{(C) } \text{Zn} + \text{dil } \text{HNO}_3 & \text{(r) } \text{N}_2\text{O} \\ \text{(D) } \text{Zn} + \text{conc } \text{HNO}_3 & \text{(s) } \text{Cu(NO}_3)_2 \\ & \text{(t) } \text{Zn(NO}_3)_2 \end{array}

Options

A

A →\rightarrow p, s

Correct
B

B →\rightarrow q, s

Correct
C

C →\rightarrow r, t

Correct
D

D →\rightarrow q, t

Correct

Topics & Concepts

p-Block Elements (Group 15-18)p-Block Elementsd-Block Elements

Step-by-Step Solution

To determine the correct matching between the reactions in Column I and the products in Column II, we write the balanced chemical equations for each reaction:

  1. Reaction (A): Cu+dilute HNO3\text{Cu} + \text{dilute } \text{HNO}_3
    Copper reacts with dilute nitric acid to form copper(II) nitrate, nitric oxide (NO\text{NO}), and water:
    3Cu+8HNO3(dil.)→3Cu(NO3)2+2NO+4H2O3\text{Cu} + 8\text{HNO}_3(\text{dil.}) \rightarrow 3\text{Cu(NO}_3)_2 + 2\text{NO} + 4\text{H}_2\text{O}

    • The products formed correspond to (p) NO\text{NO} and (s) Cu(NO3)2\text{Cu(NO}_3)_2.
    • Therefore, A→p, s\text{A} \rightarrow \text{p, s}.

  2. Reaction (B): Cu+concentrated HNO3\text{Cu} + \text{concentrated } \text{HNO}_3
    Copper reacts with concentrated nitric acid to form copper(II) nitrate, nitrogen dioxide (NO2\text{NO}_2), and water:
    Cu+4HNO3(conc.)→Cu(NO3)2+2NO2+2H2O\text{Cu} + 4\text{HNO}_3(\text{conc.}) \rightarrow \text{Cu(NO}_3)_2 + 2\text{NO}_2 + 2\text{H}_2\text{O}

    • The products formed correspond to (q) NO2\text{NO}_2 and (s) Cu(NO3)2\text{Cu(NO}_3)_2.
    • Therefore, B→q, s\text{B} \rightarrow \text{q, s}.

  3. Reaction (C): Zn+dilute HNO3\text{Zn} + \text{dilute } \text{HNO}_3
    Zinc reacts with dilute nitric acid to form zinc nitrate, nitrous oxide (N2O\text{N}_2\text{O}), and water:
    4Zn+10HNO3(dil.)→4Zn(NO3)2+N2O+5H2O4\text{Zn} + 10\text{HNO}_3(\text{dil.}) \rightarrow 4\text{Zn(NO}_3)_2 + \text{N}_2\text{O} + 5\text{H}_2\text{O}

    • The products formed correspond to (r) N2O\text{N}_2\text{O} and (t) Zn(NO3)2\text{Zn(NO}_3)_2.
    • Therefore, C→r, t\text{C} \rightarrow \text{r, t}.

  4. Reaction (D): Zn+concentrated HNO3\text{Zn} + \text{concentrated } \text{HNO}_3
    Zinc reacts with concentrated nitric acid to form zinc nitrate, nitrogen dioxide (NO2\text{NO}_2), and water:
    Zn+4HNO3(conc.)→Zn(NO3)2+2NO2+2H2O\text{Zn} + 4\text{HNO}_3(\text{conc.}) \rightarrow \text{Zn(NO}_3)_2 + 2\text{NO}_2 + 2\text{H}_2\text{O}

    • The products formed correspond to (q) NO2\text{NO}_2 and (t) Zn(NO3)2\text{Zn(NO}_3)_2.
    • Therefore, D→q, t\text{D} \rightarrow \text{q, t}.

Thus, the correct matchings are:

  • A→p, s\text{A} \rightarrow \text{p, s}
  • B→q, s\text{B} \rightarrow \text{q, s}
  • C→r, t\text{C} \rightarrow \text{r, t}
  • D→q, t\text{D} \rightarrow \text{q, t}

All given options A, B, C, D correctly describe the respective matches.

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