Match Chemical Substances with Polymer Types and Bond Types

To solve the matching problem between the chemical substances in Column I and the polymer types or bond types in Column II, we analyze each substance individually:

1. (A) Cellulose:

   • Nature: Cellulose is a naturally occurring structural carbohydrate found in the cell walls of green plants. Hence, it is a natural polymer $\rightarrow \text{(p)}$.
   • Linkage: It is a polysaccharide composed of linear chains of $\beta$-D-glucose units linked together by $\beta(1 \rightarrow 4)$ glycoside linkages $\rightarrow \text{(s)}$.
   • Therefore, (A) $\rightarrow$ p, s.

2. (B) Nylon-6,6:

   • Nature: Nylon-6,6 is a man-made condensation polymer produced by reacting hexamethylenediamine with adipic acid. Hence, it is a synthetic polymer $\rightarrow \text{(q)}$.
   • Linkage: The reaction forms repeating amide bonds ($-\text{CONH}-$) between the monomer units, making it a polyamide containing an amide linkage $\rightarrow \text{(r)}$.
   • Therefore, (B) $\rightarrow$ q, r.

3. (C) Protein:

   • Nature: Proteins are biopolymers found in living organisms composed of long chains of $\alpha$-amino acids. Hence, it is a natural polymer $\rightarrow \text{(p)}$.
   • Linkage: The amino acids are joined sequentially by peptide bonds, which are chemically amide linkages ($-\text{CONH}-$) $\rightarrow \text{(r)}$.
   • Therefore, (C) $\rightarrow$ p, r.

4. (D) Sucrose:

   • Nature: Sucrose ($\text{C}_{12}\text{H}_{22}\text{O}_{11}$) is a disaccharide (a small biomodule, not a high-molecular-weight polymer). Thus, it is neither a natural polymer nor a synthetic polymer.
   • Linkage: It consists of an $\alpha$-D-glucopyranosyl unit and a $\beta$-D-fructofuranosyl unit joined together by an $\alpha,\beta-1,2$-glycoside linkage $\rightarrow \text{(s)}$.
   • Therefore, (D) $\rightarrow$ s.

---

Final Match:

• A $\rightarrow$ p, s
• B $\rightarrow$ q, r
• C $\rightarrow$ p, r
• D $\rightarrow$ s