JEE Challenger
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Mass of Freshly Prepared Radioactive Sample Given Mean Life and Activity

The activity of a freshly prepared radioactive sample is 101010^{10} disintegrations per second, whose mean life is 109 s10^9 \text{ s}. The mass of an atom of this radioisotope is 10−25 kg10^{-25} \text{ kg}. The mass (in mg) of the radioactive sample is

Official Numerical Answer1

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Step-by-Step Solution

To find the mass of the radioactive sample, we use the fundamental laws of radioactive decay:

  1. Relation between Activity and Number of Nuclei:
    The activity AA of a radioactive sample is related to the number of undecayed radioactive nuclei NN and the decay constant λ\lambda by:
    A=λNA = \lambda N

  2. Relation between Decay Constant and Mean Life:
    The mean life τ\tau of the radioactive substance is the reciprocal of the decay constant:
    τ=1λ  ⟹  λ=1τ\tau = \frac{1}{\lambda} \implies \lambda = \frac{1}{\tau}

    Substituting this into the activity expression gives:
    A=Nτ  ⟹  N=A⋅τA = \frac{N}{\tau} \implies N = A \cdot \tau

  3. Calculating the Number of Atoms (NN):
    Given:

    • Activity, A=1010 disintegrations per second (dps)A = 10^{10} \text{ disintegrations per second (dps)}
    • Mean life, τ=109 s\tau = 10^9 \text{ s}

    N=(1010 s−1)×(109 s)=1019 atomsN = (10^{10} \text{ s}^{-1}) \times (10^9 \text{ s}) = 10^{19} \text{ atoms}

  4. Calculating the Total Mass of the Sample:
    Given the mass of a single atom, m=10−25 kgm = 10^{-25} \text{ kg}:
    M=N×m=1019×10−25 kg=10−6 kgM = N \times m = 10^{19} \times 10^{-25} \text{ kg} = 10^{-6} \text{ kg}

  5. Converting the Mass to Milligrams (mg\text{mg}):
    Since 1 kg=106 mg1 \text{ kg} = 10^6 \text{ mg}:
    M=10−6×106 mg=1 mgM = 10^{-6} \times 10^6 \text{ mg} = 1 \text{ mg}

Thus, the mass of the radioactive sample is 11.