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Identification of Iron Cyanide Complex Compound Z

The compound Z\mathbf{Z} is

Options

A

Mg2[Fe(CN)6]\mathrm{Mg}_2[\mathrm{Fe}(\mathrm{CN})_6]

B

Fe[Fe(CN)6]\mathrm{Fe}[\mathrm{Fe}(\mathrm{CN})_6]

Correct
C

Fe4[Fe(CN)6]3\mathrm{Fe}_4[\mathrm{Fe}(\mathrm{CN})_6]_3

D

K2Zn3[Fe(CN)6]2\mathrm{K}_2\mathrm{Zn}_3[\mathrm{Fe}(\mathrm{CN})_6]_2

Step-by-Step Solution

To determine the identity of compound Z\mathbf{Z}:

In the qualitative analysis of iron, the reaction of iron(III) ions (Fe3+\mathrm{Fe}^{3+}) with potassium hexacyanoferrate(III) (potassium ferricyanide, K3[Fe(CN)6]\mathrm{K}_3[\mathrm{Fe}(\mathrm{CN})_6]) yields a brown-colored complex of iron(III) hexacyanoferrate(III):

Fe3+(aq)+[Fe(CN)6]3−(aq)⟶Fe[Fe(CN)6](s/aq)\mathrm{Fe}^{3+}(\mathrm{aq}) + [\mathrm{Fe}(\mathrm{CN})_6]^{3-}(\mathrm{aq}) \longrightarrow \mathrm{Fe}[\mathrm{Fe}(\mathrm{CN})_6](\mathrm{s}/\mathrm{aq})

In this neutral coordination compound:

  • The coordination entity carries a charge of −3-3, i.e., [FeIII(CN)6]3−[\mathrm{Fe}^{\mathrm{III}}(\mathrm{CN})_6]^{3-}.
  • The counter cation is Fe3+\mathrm{Fe}^{3+}.
  • Combining these in a 1:11:1 stoichiometric ratio gives the neutral formula Fe[Fe(CN)6]\mathrm{Fe}[\mathrm{Fe}(\mathrm{CN})_6].

Therefore, the compound Z\mathbf{Z} is Fe[Fe(CN)6]\mathrm{Fe}[\mathrm{Fe}(\mathrm{CN})_6].

Hence, the correct option is (B).