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Count Liquids Deflected by Charged Comb Stream Test

Consider the following substances in liquid form: O2,HF,H2O,NH3,H2O2,CCl4,CHCl3,C6H6,C6H5Cl\text{O}_2, \text{HF}, \text{H}_2\text{O}, \text{NH}_3, \text{H}_2\text{O}_2, \text{CCl}_4, \text{CHCl}_3, \text{C}_6\text{H}_6, \text{C}_6\text{H}_5\text{Cl}.

When a charged comb is brought close to their flowing stream, how many of these liquids exhibit deflection as illustrated in the figure?

Question Diagram 1
Official Numerical Answer6

Step-by-Step Solution

To determine the number of liquid streams deflected by a charged comb, we use the principle of electrostatic deflection of liquids containing polar molecules.

Principle:

When a charged object (such as a comb) is brought near a stream of a liquid, the electric field generated by the charge creates a non-uniform field.

  • Liquids composed of polar molecules (μ≠0\mu \neq 0, having a permanent dipole moment) experience an attractive electrostatic force regardless of whether the comb is positively or negatively charged, causing the stream to deflect toward the comb.
  • Liquids composed of non-polar molecules (μ=0\mu = 0) do not possess a permanent dipole moment and do not show observable deflection.

Analysis of the Given Liquids:

  1. O2\text{O}_2 (Liquid Oxygen):

    • A homonuclear diatomic molecule.
    • Dipole moment: μ=0\mu = 0 (Non-polar →\rightarrow No deflection).
  2. HF\text{HF} (Liquid Hydrogen Fluoride):

    • Heteronuclear diatomic molecule with high electronegativity difference between H\text{H} and F\text{F}.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).
  3. H2O\text{H}_2\text{O} (Water):

    • Bent (V-shaped) geometry with lone pairs on oxygen, breaking symmetry.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).
  4. NH3\text{NH}_3 (Liquid Ammonia):

    • Trigonal pyramidal geometry with a lone pair on nitrogen.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).
  5. H2O2\text{H}_2\text{O}_2 (Hydrogen Peroxide):

    • Non-planar open-book structure, leading to a net dipole moment.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).
  6. CCl4\text{CCl}_4 (Carbon Tetrachloride):

    • Highly symmetrical tetrahedral structure (TdT_d symmetry) where individual C-Cl\text{C-Cl} bond dipoles cancel each other out completely.
    • Dipole moment: μ=0\mu = 0 (Non-polar →\rightarrow No deflection).
  7. CHCl3\text{CHCl}_3 (Chloroform):

    • Asymmetrical tetrahedral structure where bond dipoles do not cancel out.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).
  8. C6H6\text{C}_6\text{H}_6 (Benzene):

    • Symmetrical planar hexagonal ring (D6hD_{6h} symmetry).
    • Dipole moment: μ=0\mu = 0 (Non-polar →\rightarrow No deflection).
  9. C6H5Cl\text{C}_6\text{H}_5\text{Cl} (Chlorobenzene):

    • Asymmetric polar molecule due to the electronegative chlorine atom attached to the benzene ring.
    • Dipole moment: μ≠0\mu \neq 0 (Polar →\rightarrow Deflected).

Conclusion:

The liquids that exhibit deflection are those with μ≠0\mu \neq 0: HF,H2O,NH3,H2O2,CHCl3,and C6H5Cl\text{HF}, \text{H}_2\text{O}, \text{NH}_3, \text{H}_2\text{O}_2, \text{CHCl}_3, \text{and } \text{C}_6\text{H}_5\text{Cl}

Total number of liquids showing deflection =6= 6.