JEE Challenger
More from Biomolecules

Chemical Properties and Structure of Carbohydrates

Identify the true statement(s) from the choices below:

Options

A

Monosaccharides cannot undergo hydrolysis to yield polyhydroxy aldehydes and ketones

Correct
B

Oxidation of glucose using bromine water yields glutamic acid

C

Hydrolysis of sucrose yields dextrorotatory glucose alongside laevorotatory fructose

Correct
D

The pair of six-membered cyclic hemiacetal structures of D-(+)-glucose are termed anomers

Correct

Topics & Concepts

Step-by-Step Solution

To determine the correct statements, let us analyze each option individually:

  1. Option (A):

    • Definition: Monosaccharides are the simplest carbohydrates. By definition, they cannot be hydrolyzed further into smaller units of polyhydroxy aldehydes or ketones.
    • Therefore, statement (A) is true.
  2. Option (B):

    • Reaction: Bromine water (Br2/H2O\text{Br}_2 / \text{H}_2\text{O}) is a mild oxidizing agent that selectively oxidizes the aldehyde group (−CHO-\text{CHO}) of D-glucose into a carboxylic acid group (−COOH-\text{COOH}), forming gluconic acid: CHO−(CHOH)4−CH2OH→Br2/H2OCOOH−(CHOH)4−CH2OH(Gluconic acid)\text{CHO}-(\text{CHOH})_4-\text{CH}_2\text{OH} \xrightarrow{\text{Br}_2 / \text{H}_2\text{O}} \text{COOH}-(\text{CHOH})_4-\text{CH}_2\text{OH} \quad (\text{Gluconic acid})
    • Glutamic acid is an amino acid (HOOC−CH2−CH2−CH(NH2)−COOH\text{HOOC}-\text{CH}_2-\text{CH}_2-\text{CH}(\text{NH}_2)-\text{COOH}) and is not formed in this reaction.
    • Therefore, statement (B) is false.
  3. Option (C):

    • Sucrose Hydrolysis: Sucrose is a non-reducing disaccharide that undergoes hydrolysis in the presence of dilute acid or the enzyme invertase to produce equal amounts of D-(+)-glucose and D-(-)-fructose: C12H22O11+H2O→H+C6H12O6D-glucose (Dextrorotatory, +52.5∘)+C6H12O6D-fructose (Laevorotatory, −92.4∘)\text{C}_{12}\text{H}_{22}\text{O}_{11} + \text{H}_2\text{O} \xrightarrow{\text{H}^+} \underset{\text{D-glucose (Dextrorotatory, } +52.5^\circ\text{)}}{\text{C}_6\text{H}_{12}\text{O}_6} + \underset{\text{D-fructose (Laevorotatory, } -92.4^\circ\text{)}}{\text{C}_6\text{H}_{12}\text{O}_6}
    • Therefore, statement (C) is true.
  4. Option (D):

    • Anomers of Glucose: D-(+)-glucose exists in two six-membered cyclic hemiacetal forms, namely α-D-(+)\alpha\text{-D-(+)}-glucopyranose and β-D-(+)\beta\text{-D-(+)}-glucopyranose.
    • These two forms differ in configuration only at the C-1 carbon atom (the hemiacetal or anomeric carbon). Stereoisomers that differ only in configuration at C-1 are termed anomers.
    • Therefore, statement (D) is true.

Correct Options: (A), (C), (D)