JEE Challenger
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Basicity Order of Nitrogenous Organic Compounds

Identify the correct order of basicity for the organic compounds labeled I, II, III, and IV below:

Question Diagram 1

Options

A

II>I>IV>III\text{II} > \text{I} > \text{IV} > \text{III}

B

IV>II>III>I\text{IV} > \text{II} > \text{III} > \text{I}

C

IV>I>II>III\text{IV} > \text{I} > \text{II} > \text{III}

Correct
D

I>IV>III>II\text{I} > \text{IV} > \text{III} > \text{II}

Step-by-Step Solution

To determine the correct order of basicity for the given organic compounds, we evaluate the stability of their respective conjugate acids formed upon protonation:

  1. Compound IV (Guanidine, HN=C(NH2)2\text{HN}=\text{C}(\text{NH}_2)_2): Protonation takes place at the imine (sp2sp^2-hybridized) nitrogen atom. The resulting conjugate acid [C(NH2)3]+[\text{C}(\text{NH}_2)_3]^+ is exceptionally stable because the positive charge is delocalized equally over three equivalent nitrogen atoms through resonance: H2N+=C(NH2)2⟷H2N−C(=NH2+)−NH2⟷H2N−C(NH2)=NH2+\text{H}_2\text{N}^+=\text{C}(\text{NH}_2)_2 \longleftrightarrow \text{H}_2\text{N}-\text{C}(=\text{NH}_2^+)-\text{NH}_2 \longleftrightarrow \text{H}_2\text{N}-\text{C}(\text{NH}_2)=\text{NH}_2^+ Due to this symmetric and extensive resonance stabilization, guanidine is the strongest base among the given compounds (pKa of conjugate acid≈13.6pK_a \text{ of conjugate acid} \approx 13.6).

  2. Compound I (Acetamidine, CH3−C(=NH)NH2\text{CH}_3-\text{C}(=\text{NH})\text{NH}_2): Protonation occurs at the sp2sp^2 imine nitrogen. The conjugate acid is stabilized by two equivalent resonance structures: CH3−C(=NH2+)−NH2⟷CH3−C(NH2)=NH2+\text{CH}_3-\text{C}(=\text{NH}_2^+)-\text{NH}_2 \longleftrightarrow \text{CH}_3-\text{C}(\text{NH}_2)=\text{NH}_2^+ Furthermore, the methyl group (−CH3-\text{CH}_3) exerts a strong +I+I (inductive) effect that stabilizes the positive charge, making it more basic than its cyclic counterpart (pKa of conjugate acid≈12.4pK_a \text{ of conjugate acid} \approx 12.4).

  3. Compound II (2-Imidazoline): This is a non-aromatic cyclic amidine. Protonation at the sp2sp^2 nitrogen leads to a conjugate acid stabilized by resonance across two nitrogen atoms. However, due to ring constraints and the lack of a methyl group providing a direct +I+I effect, it is slightly less basic than acetamidine (pKa of conjugate acid≈11.0pK_a \text{ of conjugate acid} \approx 11.0).

  4. Compound III (Imidazole): Imidazole is an aromatic compound where the lone pair on the pyrrole-like nitrogen (−NH−-\text{NH}-) is part of the 6π6\pi-electron aromatic system. Protonation occurs at the pyridine-like sp2sp^2 nitrogen (=N−=\text{N}-). Although the conjugate acid is resonance-stabilized, the high initial aromatic stability of neutral imidazole reduces its tendency to accept a proton compared to non-aromatic amidines and guanidines (pKa of conjugate acid≈6.95pK_a \text{ of conjugate acid} \approx 6.95).

Comparing the pKapK_a values of the conjugate acids, the order of basicity is: IV>I>II>III\text{IV} > \text{I} > \text{II} > \text{III}

Therefore, the correct option is C.