Basicity Order of Nitrogenous Organic Compounds
Identify the correct order of basicity for the organic compounds labeled I, II, III, and IV below:

Options
Topics & Concepts
Step-by-Step Solution
To determine the correct order of basicity for the given organic compounds, we evaluate the stability of their respective conjugate acids formed upon protonation:
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Compound IV (Guanidine, ): Protonation takes place at the imine (-hybridized) nitrogen atom. The resulting conjugate acid is exceptionally stable because the positive charge is delocalized equally over three equivalent nitrogen atoms through resonance: Due to this symmetric and extensive resonance stabilization, guanidine is the strongest base among the given compounds ().
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Compound I (Acetamidine, ): Protonation occurs at the imine nitrogen. The conjugate acid is stabilized by two equivalent resonance structures: Furthermore, the methyl group () exerts a strong (inductive) effect that stabilizes the positive charge, making it more basic than its cyclic counterpart ().
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Compound II (2-Imidazoline): This is a non-aromatic cyclic amidine. Protonation at the nitrogen leads to a conjugate acid stabilized by resonance across two nitrogen atoms. However, due to ring constraints and the lack of a methyl group providing a direct effect, it is slightly less basic than acetamidine ().
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Compound III (Imidazole): Imidazole is an aromatic compound where the lone pair on the pyrrole-like nitrogen () is part of the -electron aromatic system. Protonation occurs at the pyridine-like nitrogen (). Although the conjugate acid is resonance-stabilized, the high initial aromatic stability of neutral imidazole reduces its tendency to accept a proton compared to non-aromatic amidines and guanidines ().
Comparing the values of the conjugate acids, the order of basicity is:
Therefore, the correct option is C.