JEE Challenger
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Acidic Hydrolysis Rate of Substituted Trityl Ether Derivatives

The rate of acid-catalyzed hydrolysis of the given ether (X)(\mathbf{X}) occurs most rapidly when:

Question Diagram 1

Options

A

a methyl group replaces one phenyl ring.

B

a parapara-methoxyphenyl group replaces one phenyl ring.

C

two parapara-methoxyphenyl groups replace two phenyl rings.

Correct
D

no structural modification is done to X\mathbf{X}.

Step-by-Step Solution

The rate of acid-catalyzed hydrolysis of an ether depends strongly on the stability of the intermediate formed during the reaction.

1. Reaction Mechanism:

The acid-catalyzed hydrolysis of the trityl ether derivative (X\mathbf{X}) proceeds via an SN1\text{S}_\text{N}1 mechanism due to the steric hindrance and the high stability of the triarylmethyl cation formed as an intermediate:

  1. Protonation of Ether: Ar3C-O-R+H+⇌Ar3C−O+H−R\text{Ar}_3\text{C-O-R} + \text{H}^+ \rightleftharpoons \text{Ar}_3\text{C}-\overset{+}{\text{O}}\text{H}-\text{R}

  2. Heterolytic Cleavage (Rate-Determining Step, RDS): Ar3C−O+H−R→slowAr3C++ROH\text{Ar}_3\text{C}-\overset{+}{\text{O}}\text{H}-\text{R} \xrightarrow{\text{slow}} \text{Ar}_3\text{C}^+ + \text{ROH}

  3. Nucleophilic Attack by Water: Ar3C++H2O→fastAr3C-OH+H+\text{Ar}_3\text{C}^+ + \text{H}_2\text{O} \xrightarrow{\text{fast}} \text{Ar}_3\text{C-OH} + \text{H}^+

2. Factors Affecting the Reaction Rate:

Since step 2 is the rate-determining step, any factor that increases the stability of the carbocation intermediate (Ar3C+\text{Ar}_3\text{C}^+) lowers the activation energy (ΔG‡\Delta G^\ddagger) of the transition state, thereby accelerating the rate of hydrolysis.

3. Evaluation of Options:

  • Replacing a phenyl ring with a methyl group (Option A): A methyl group stabilizes a carbocation via hyperconjugation and inductive effects (+I+I), whereas a phenyl ring stabilizes it via extensive π\pi-delocalization (resonance). Replacing a phenyl ring with a methyl group reduces resonance stabilization, making the carbocation less stable and decreasing the reaction rate.

  • Original Molecule X\mathbf{X} (Option D): The triphenylmethyl (trityl) carbocation, Ph3C+\text{Ph}_3\text{C}^+, is stabilized by resonance across three phenyl rings.

  • Replacing one phenyl group with a parapara-methoxyphenyl group (Option B): The parapara-methoxy (p-OCH3p\text{-OCH}_3) substituent is a strong electron-donating group through its mesomeric effect (+M+M). The lone pair of electrons on the oxygen atom delocalizes effectively into the ring and onto the central carbocation: H3C−O¨−C6H4−C+⟷H3C−O+=C6H4=C\text{H}_3\text{C}-\ddot{\text{O}}-\text{C}_6\text{H}_4-\text{C}^+ \longleftrightarrow \text{H}_3\text{C}-\overset{+}{\text{O}}=\text{C}_6\text{H}_4=\text{C} This significant +M+M stabilization increases the carbocation stability relative to X\mathbf{X}.

  • Replacing two phenyl groups with two parapara-methoxyphenyl groups (Option C): Having two parapara-methoxyphenyl groups introduces two strong +M+M electron-donating groups. The additive resonance contribution of both methoxy groups stabilizes the positive charge on the central carbon atom to an even greater extent than a single parapara-methoxyphenyl group.

Conclusion:

The carbocation formed when two phenyl groups are replaced by two parapara-methoxyphenyl groups is the most stable among all the choices, leading to the lowest activation energy and the fastest rate of hydrolysis.

Thus, the correct option is C.