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Velocity of a Plane Progressive Wave

The equation of a plane progressive wave is given by y=5cosπ(200tx150)y = 5 \cos \pi \left(200 t - \frac{x}{150}\right) where xx and yy are in cm and tt is in second. The velocity of the wave is ________ m/s\text{m/s}.

Options

A

120

B

150

C

200

D

300

Correct

Topics & Concepts

WavesWave Equation

Step-by-Step Solution

The given equation of the plane progressive wave is: y=5cosπ(200tx150)y = 5 \cos \pi \left(200 t - \frac{x}{150}\right)

Expanding the argument inside the cosine function, we get: y=5cos(200πtπx150)y = 5 \cos \left(200\pi t - \frac{\pi x}{150}\right)

Comparing this with the standard form of a progressive wave equation: y=Acos(ωtkx)y = A \cos(\omega t - kx)

we identify the angular frequency (ω\omega) and the propagation constant (kk) as: ω=200π rad/s\omega = 200\pi \text{ rad/s} k=π150 rad/cmk = \frac{\pi}{150} \text{ rad/cm}

The velocity of the wave (vv) is given by the relation: v=ωkv = \frac{\omega}{k}

Substituting the values of ω\omega and kk: v=200ππ150=200×150=30000 cm/sv = \frac{200\pi}{\frac{\pi}{150}} = 200 \times 150 = 30000 \text{ cm/s}

Converting the wave velocity from cm/s\text{cm/s} to m/s\text{m/s}: v=30000100 m/s=300 m/sv = \frac{30000}{100} \text{ m/s} = 300 \text{ m/s}

Hence, the velocity of the wave is 300 m/s300 \text{ m/s}, which corresponds to option D.

Velocity of a Plane Progressive Wave | Physics PYQ Solution - JEE Challenger