To find the vector(s) coplanar with the vectors a=i^+j^+2k^ and b=i^+2j^+k^, and perpendicular to c=i^+j^+k^, we can express the required vector r as a linear combination of a and b:
r=λa+μb
Substituting the components of a and b: r=λ(i^+j^+2k^)+μ(i^+2j^+k^) r=(λ+μ)i^+(λ+2μ)j^+(2λ+μ)k^
Since r is perpendicular to c=i^+j^+k^, their dot product must be zero: r⋅c=0 (λ+μ)(1)+(λ+2μ)(1)+(2λ+μ)(1)=0 4λ+4μ=0⟹λ+μ=0⟹μ=−λ
Substituting μ=−λ back into the expression for r: r=(λ−λ)i^+(λ−2λ)j^+(2λ−λ)k^ r=−λj^+λk^=λ(−j^+k^)
For λ=−1, we get: r=j^−k^
which corresponds to option (A).
For λ=1, we get: r=−j^+k^
which corresponds to option (D).