To find the value of the given expression, we analyze the properties of the functional equations for f(x) and g(x).
Step 1: Evaluation of f(41)
The function f:R→R satisfies Cauchy's additive functional equation:
f(x+y)=f(x)+f(y)for all x,y∈R
By mathematical induction, for any rational number r∈Q and any x∈R, we have:
f(rx)=rf(x)
We are given f(−53)=12. Expressing 41 in terms of −53, we have:
41=(−125)×(−53)
Since −125 is a rational number, we apply the property:
f(41)=f(−125⋅(−53))=−125f(−53)
Substitute f(−53)=12:
f(41)=−125×12=−5
Step 2: Evaluation of g(0) and g(−2)
The function g:R→(0,∞) satisfies the exponential functional equation:
g(x+y)=g(x)g(y)for all x,y∈R
-
Finding g(0):
Setting x=y=0:
g(0)=g(0+0)=g(0)g(0)=(g(0))2
Since the codomain of g is (0,∞), g(0)=0. Dividing both sides by g(0), we get:
g(0)=1
-
Finding g(−2):
For any rational number r∈Q and any x∈R, the relation g(rx)=(g(x))r holds.
Expressing −2 in terms of −31, we have:
−2=6×(−31)
Therefore:
g(−2)=g(6⋅(−31))=(g(−31))6
Given g(−31)=2:
g(−2)=26=64
Step 3: Calculating the Final Expression
We substitute f(41)=−5, g(−2)=64, and g(0)=1 into the target expression:
(f(41)+g(−2)−8)g(0)=(−5+64−8)×1
=(59−8)×1=51
Thus, the value of the expression is 51.