Stereoisomers of D Configuration Aldohexose in Pyranose Form
For the given aldohexose structure:
When this compound exists in its -configuration, determine the total count of stereoisomers present in its pyranose form.
Topics & Concepts
Step-by-Step Solution
To determine the total number of stereoisomers in the pyranose form of the given aldohexose in its -configuration, we analyze the structure step-by-step:
1. Structure Analysis of the Open-Chain Form
The given aldohexose structure is:
2. Pyranose Ring Formation
A pyranose ring is a 6-membered ring consisting of 5 carbon atoms and 1 oxygen atom. It is formed by the intramolecular nucleophilic attack of the hydroxyl group () attached to C5 onto the aldehyde carbonyl carbon (C1).
The resulting ring backbone is:
3. Stereocenters in the Pyranose Form
Let us evaluate each carbon atom in the cyclic pyranose form to identify the active chiral centers and their degrees of freedom:
-
(Anomeric Carbon): Upon cyclic hemiacetal formation, becomes a new asymmetric center (anomeric carbon) bonded to four distinct groups (, , , ). It can exist in two distinct configurations ( and anomers).
-
: Contains two hydrogen atoms (), making it achiral.
-
: Attached to four different groups (, , , ), so it is a chiral center with two possible configurations ( or ).
-
: Attached to four different groups (, , , ), so it is a chiral center with two possible configurations ( or ).
-
: This is the stereocenter that defines the configuration of the carbohydrate. Since the problem explicitly specifies that the molecule is in its -configuration, the spatial arrangement at is fixed.
-
: Contains a group, making it achiral.
4. Total Count of Stereoisomers
The total number of stereoisomers for the -configuration in the pyranose form is given by the product of the possible configurations at each chiral center: