JEE Challenger
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Stereoisomers of D Configuration Aldohexose in Pyranose Form

For the given aldohexose structure:

CHO∣CH2∣CHOH∣CHOH∣CHOH∣CH2OH\begin{array}{c} \text{CHO} \\ | \\ \text{CH}_2 \\ | \\ \text{CHOH} \\ | \\ \text{CHOH} \\ | \\ \text{CHOH} \\ | \\ \text{CH}_2\text{OH} \end{array}

When this compound exists in its D\text{D}-configuration, determine the total count of stereoisomers present in its pyranose form.

Official Numerical Answer8

Topics & Concepts

Step-by-Step Solution

To determine the total number of stereoisomers in the pyranose form of the given aldohexose in its D\text{D}-configuration, we analyze the structure step-by-step:

1. Structure Analysis of the Open-Chain Form

The given aldohexose structure is:

C1: CHO∣C2: CH2∣C3: CHOH∣C4: CHOH∣C5: CHOH∣C6: CH2OH\begin{array}{c} \text{C1: CHO} \\ | \\ \text{C2: CH}_2 \\ | \\ \text{C3: CHOH} \\ | \\ \text{C4: CHOH} \\ | \\ \text{C5: CHOH} \\ | \\ \text{C6: CH}_2\text{OH} \end{array}

2. Pyranose Ring Formation

A pyranose ring is a 6-membered ring consisting of 5 carbon atoms and 1 oxygen atom. It is formed by the intramolecular nucleophilic attack of the hydroxyl group (−OH-\text{OH}) attached to C5 onto the aldehyde carbonyl carbon (C1).

The resulting ring backbone is: C1−C2−C3−C4−C5−O−C1\text{C1} - \text{C2} - \text{C3} - \text{C4} - \text{C5} - \text{O} - \text{C1}

3. Stereocenters in the Pyranose Form

Let us evaluate each carbon atom in the cyclic pyranose form to identify the active chiral centers and their degrees of freedom:

  1. C1\text{C1} (Anomeric Carbon): Upon cyclic hemiacetal formation, C1\text{C1} becomes a new asymmetric center (anomeric carbon) bonded to four distinct groups (−H-\text{H}, −OH-\text{OH}, −O−-\text{O}-, −CH2−-\text{CH}_2-). It can exist in two distinct configurations (α\alpha and β\beta anomers). Number of configurations at C1=2\text{Number of configurations at C1} = 2

  2. C2\text{C2}: Contains two hydrogen atoms (−CH2−-\text{CH}_2-), making it achiral. Number of configurations at C2=1\text{Number of configurations at C2} = 1

  3. C3\text{C3}: Attached to four different groups (−H-\text{H}, −OH-\text{OH}, −CH2−-\text{CH}_2-, −CHOH−-\text{CHOH}-), so it is a chiral center with two possible configurations (RR or SS). Number of configurations at C3=2\text{Number of configurations at C3} = 2

  4. C4\text{C4}: Attached to four different groups (−H-\text{H}, −OH-\text{OH}, −CHOH−-\text{CHOH}-, −CH(CH2OH)−-\text{CH}(\text{CH}_2\text{OH})-), so it is a chiral center with two possible configurations (RR or SS). Number of configurations at C4=2\text{Number of configurations at C4} = 2

  5. C5\text{C5}: This is the stereocenter that defines the D/L\text{D/L} configuration of the carbohydrate. Since the problem explicitly specifies that the molecule is in its D\text{D}-configuration, the spatial arrangement at C5\text{C5} is fixed. Number of configurations at C5=1\text{Number of configurations at C5} = 1

  6. C6\text{C6}: Contains a −CH2OH-\text{CH}_2\text{OH} group, making it achiral. Number of configurations at C6=1\text{Number of configurations at C6} = 1

4. Total Count of Stereoisomers

The total number of stereoisomers for the D\text{D}-configuration in the pyranose form is given by the product of the possible configurations at each chiral center:

Total Stereoisomers=2(at C1)×2(at C3)×2(at C4)×1(at C5)=23=8\text{Total Stereoisomers} = 2_{\text{(at C1)}} \times 2_{\text{(at C3)}} \times 2_{\text{(at C4)}} \times 1_{\text{(at C5)}} = 2^3 = 8