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Statements on Laws of Thermodynamics and Variable Types

Consider the following statements: A. Zeroth law of thermodynamics gives concept of temperature B. First law of thermodynamics gives concept of internal energy C. In isothermal expansion of ideal gas, ΔQΔW\Delta Q \neq \Delta W D. Product of intensive and extensive variables is extensive E. The ratio of any extensive variable to mass will be an extensive variable

Choose the correct combination of statements from the options given below:

Options

A

C, D and E Only

B

A, B and C Only

C

A, B and D Only

Correct
D

B, C and D Only

Topics & Concepts

Step-by-Step Solution

To determine the correct combination of statements, let us analyze each statement individually:

  1. Statement A: Zeroth law of thermodynamics gives concept of temperature

    • Analysis: The Zeroth Law of Thermodynamics states that if two systems are each in thermal equilibrium with a third system, they are in thermal equilibrium with each other. This introduces the fundamental concept of a scalar property called temperature, which determines whether systems are in thermal equilibrium.
    • Status: True
  2. Statement B: First law of thermodynamics gives concept of internal energy

    • Analysis: The First Law of Thermodynamics is a statement of the principle of conservation of energy: ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W It establishes the existence of a state function called internal energy (ΔU\Delta U).
    • Status: True
  3. Statement C: In isothermal expansion of ideal gas, ΔQΔW\Delta Q \neq \Delta W

    • Analysis: For an ideal gas undergoing an isothermal process, the temperature TT remains constant (ΔT=0\Delta T = 0). Since the internal energy of an ideal gas depends solely on its temperature, the change in internal energy is zero (ΔU=0\Delta U = 0). Applying the First Law of Thermodynamics: ΔQ=ΔU+ΔW    ΔQ=ΔW\Delta Q = \Delta U + \Delta W \implies \Delta Q = \Delta W Therefore, the statement ΔQΔW\Delta Q \neq \Delta W is false.
    • Status: False
  4. Statement D: Product of intensive and extensive variables is extensive

    • Analysis: Let an intensive variable be II (which remains invariant when system size is scaled by a factor λ\lambda, i.e., III \to I) and an extensive variable be EE (which scales linearly with system size, i.e., EλEE \to \lambda E).
    • The product P=I×EP = I \times E scales as: P=I×(λE)=λ(I×E)=λPP' = I \times (\lambda E) = \lambda (I \times E) = \lambda P Since the product scales proportionally with the system size, it is an extensive variable. For example, Pressure PP (intensive) ×\times Volume VV (extensive) =PV= PV (work/energy, which is extensive).
    • Status: True
  5. Statement E: The ratio of any extensive variable to mass will be an extensive variable

    • Analysis: When an extensive variable EE is divided by mass mm (which is also extensive), both quantities scale linearly with system size λ\lambda: Em=λEλm=Em\frac{E'}{m'} = \frac{\lambda E}{\lambda m} = \frac{E}{m} Since the ratio remains invariant under scaling, it represents a specific property (e.g., specific volume v=V/mv = V/m), which is an intensive variable, not extensive.
    • Status: False

Conclusion

The correct statements are A, B and D Only.

Correct Option: C

Statements on Laws of Thermodynamics and Variable Types | Physics PYQ Solution - JEE Challenger