Statements on Hoffmann Bromamide Degradation Reaction

To determine the correct statements regarding the Hoffmann Bromamide Degradation Reaction, let us analyze the balanced general chemical equation for this reaction:

$\text{R-CONH}_2 + \text{Br}_2 + 4\text{NaOH} \rightarrow \text{R-NH}_2 + \text{Na}_2\text{CO}_3 + 2\text{NaBr} + 2\text{H}_2\text{O}$

Now, let us evaluate each statement individually:

1. Statement A: "In Hoffmann bromamide degradation, $4\text{ moles of NaOH}$ and $2\text{ moles of Br}_2$ are consumed per mole of an amide."

   • From the stoichiometric coefficients in the balanced reaction, $1\text{ mole of Br}_2$ and $4\text{ moles of NaOH}$ are consumed per mole of a primary amide.
   • Since Statement A mentions $2\text{ moles of Br}_2$, it is Incorrect (False).

2. Statement B: "Hoffmann bromamide reaction is not given by alkyl amides."

   • Both aliphatic (alkyl) and aromatic (aryl) primary amides undergo the Hoffmann bromamide degradation to yield the corresponding primary amines containing one carbon atom less.
   • Therefore, Statement B is Incorrect (False).

3. Statement C: "Primary amines can be synthesized by Hoffmann bromamide degradation."

   • The reaction specifically converts primary amides ($\text{R-CONH}_2$) into primary amines ($\text{R-NH}_2$).
   • Therefore, Statement C is Correct (True).

4. Statement D: "Secondary amide on reaction with $\text{Br}_2$ and $\text{NaOH}$ will give secondary amine."

   • The reaction mechanism requires two hydrogen atoms on the nitrogen of the amide group ($\text{-CONH}_2$) to proceed through the formation of an $N$-bromoamide intermediate followed by base-induced elimination to form an acyl nitrene/isocyanates intermediate ($\text{R-N=C=O}$).
   • Secondary amides ($\text{R-CO-NHR'}$) lack the second acidic hydrogen atom on nitrogen and thus do not undergo this degradation to yield secondary amines.
   • Therefore, Statement D is Incorrect (False).

5. Statement E: "The by-products of Hoffmann degradation are $\text{Na}_2\text{CO}_3$, $\text{NaBr}$ and $\text{H}_2\text{O}$."

   • According to the balanced equation, the side products (by-products) formed alongside the primary amine are sodium carbonate ($\text{Na}_2\text{CO}_3$), sodium bromide ($\text{NaBr}$), and water ($\text{H}_2\text{O}$).
   • Therefore, Statement E is Correct (True).

Thus, only statements C and E are true.

Correct Option: C ($\text{C and E only}$)