JEE Challenger
More from Some Basic Concepts of Chemistry

Significant Figures in Average Titre Volume Calculation

A student performs a titration with different burettes and finds titre values of 25.2 mL25.2\text{ mL}, 25.25 mL25.25\text{ mL}, and 25.0 mL25.0\text{ mL}. The number of significant figures in the average titre value is

Official Numerical Answer3

Step-by-Step Solution

To find the number of significant figures in the average titre value, we follow the rules for significant figures during mathematical operations (addition and division).

Step 1: Calculate the sum of the titre values
Sum=25.2 mL+25.25 mL+25.0 mL=75.45 mL\text{Sum} = 25.2\text{ mL} + 25.25\text{ mL} + 25.0\text{ mL} = 75.45\text{ mL}

In addition, the result must be rounded off to the same number of decimal places as the value with the fewest decimal places:

  • 25.2 mL25.2\text{ mL} has 11 decimal place.
  • 25.25 mL25.25\text{ mL} has 22 decimal places.
  • 25.0 mL25.0\text{ mL} has 11 decimal place.

The fewest number of decimal places is 11 (tenths place). Thus, the sum is reported as 75.5 mL75.5\text{ mL}, which contains 33 significant figures.

Step 2: Calculate the average value
Average titre value=75.45 mL3=25.15 mL\text{Average titre value} = \frac{75.45\text{ mL}}{3} = 25.15\text{ mL}

Here, the number 33 is an exact count (exact number) and has an infinite number of significant figures. Therefore, the division result is limited by the number of significant figures/decimal places of the numerator.

Rounding 25.15 mL25.15\text{ mL} to 11 decimal place (matching the precision of 11 decimal place from the sum) gives:
Average titre value=25.2 mL\text{Average titre value} = 25.2\text{ mL}

Step 3: Determine the number of significant figures
The final value 25.2 mL25.2\text{ mL} has 33 significant figures.