JEE Challenger
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Significant Digits in Universal Gas Constant Calculation

Given that Avogadro's number is 6.023×1023 mol−16.023 \times 10^{23} \text{ mol}^{-1} and the Boltzmann constant equals 1.380×10−23 J K−11.380 \times 10^{-23} \text{ J K}^{-1}, find the number of significant figures present in the computed value of the universal gas constant.

Official Numerical Answer4

Step-by-Step Solution

To find the number of significant figures in the computed value of the universal gas constant (RR), we use the relationship between the universal gas constant, Avogadro's number (NAN_A), and the Boltzmann constant (kBk_B):

R=NA×kBR = N_A \times k_B

Given the values from the problem:

  1. Avogadro's number, NA=6.023×1023 mol−1N_A = 6.023 \times 10^{23} \text{ mol}^{-1}

    • Number of significant figures in NA=4N_A = 4 (the digits are 6, 0, 2, and 3).
  2. Boltzmann constant, kB=1.380×10−23 J K−1k_B = 1.380 \times 10^{-23} \text{ J K}^{-1}

    • Number of significant figures in kB=4k_B = 4 (the digits are 1, 3, 8, and 0).

According to the rules for significant figures in multiplication, the final result must retain the same number of significant figures as the term with the fewest significant figures.

Calculating RR: R=(6.023×1023)×(1.380×10−23) J K−1mol−1R = (6.023 \times 10^{23}) \times (1.380 \times 10^{-23}) \text{ J K}^{-1} \text{mol}^{-1} R=6.023×1.380=8.31174 J K−1mol−1R = 6.023 \times 1.380 = 8.31174 \text{ J K}^{-1} \text{mol}^{-1}

Rounding 8.311748.31174 to 44 significant figures gives: R≈8.312 J K−1mol−1R \approx 8.312 \text{ J K}^{-1} \text{mol}^{-1}

Thus, the number of significant figures in the calculated value of the universal gas constant is 44.