JEE Challenger
More from Organic Chemistry - Basic Principles

Separation of Binary Organic Mixture by Differential Extraction

Select the binary mixture(s) capable of being isolated into constituent compounds via differential extraction using the illustrated scheme.

Question Diagram 1

Options

A

C6H5OH\mathrm{C_6H_5OH} and C6H5COOH\mathrm{C_6H_5COOH}

B

C6H5COOH\mathrm{C_6H_5COOH} and C6H5CH2OH\mathrm{C_6H_5CH_2OH}

Correct
C

C6H5CH2OH\mathrm{C_6H_5CH_2OH} and C6H5OH\mathrm{C_6H_5OH}

D

C6H5CH2OH\mathrm{C_6H_5CH_2OH} and C6H5CH2COOH\mathrm{C_6H_5CH_2COOH}

Correct

Step-by-Step Solution

To determine which binary mixture(s) can be separated into individual compounds by differential extraction using both aqueous NaOH\text{NaOH} and aqueous NaHCO3\text{NaHCO}_3 as shown in the given scheme, we evaluate the acidic properties and chemical reactivities of the components in each mixture.


1. Principles of Differential Extraction

When an organic binary mixture containing two non-polar/organic-soluble compounds is treated with an aqueous basic solution:

  1. If a compound is sufficiently acidic, it reacts with the base to form a water-soluble ionic salt: Acidic Compound+Base(aq)⟶Ionic Salt(aq)(Aqueous Layer)\text{Acidic Compound} + \text{Base}(aq) \longrightarrow \text{Ionic Salt}(aq) \quad (\text{Aqueous Layer})
  2. If a compound is neutral or exceedingly weakly acidic, it does not react with the base and remains in the organic solvent: Neutral/Weakly Acidic Compound⟶Unreacted(Organic Layer)\text{Neutral/Weakly Acidic Compound} \longrightarrow \text{Unreacted} \quad (\text{Organic Layer})

For a mixture to be successfully separated into Compound 1 and Compound 2 by both NaOH(aq)\text{NaOH}(aq) and NaHCO3(aq)\text{NaHCO}_3(aq) individually (as shown in the scheme), one compound must react with both reagents while the other compound must react with neither.


2. Acidity and Reactivity Comparison

  • Carboxylic Acids (R-COOH\text{R-COOH}), such as Benzoic acid (C6H5COOH\text{C}_6\text{H}_5\text{COOH}) and Phenylacetic acid (C6H5CH2COOH\text{C}_6\text{H}_5\text{CH}_2\text{COOH}):

    • pKa≈4−5pK_a \approx 4 - 5
    • React with both strong bases like NaOH\text{NaOH} and weak bases like NaHCO3\text{NaHCO}_3: R-COOH+NaOH(aq)⟶R-COO−Na+(aq)+H2O\text{R-COOH} + \text{NaOH}(aq) \longrightarrow \text{R-COO}^-\text{Na}^+(aq) + \text{H}_2\text{O} R-COOH+NaHCO3(aq)⟶R-COO−Na+(aq)+H2O+CO2↑\text{R-COOH} + \text{NaHCO}_3(aq) \longrightarrow \text{R-COO}^-\text{Na}^+(aq) + \text{H}_2\text{O} + \text{CO}_2\uparrow
  • Alcohols (R-OH\text{R-OH}), such as Benzyl alcohol (C6H5CH2OH\text{C}_6\text{H}_5\text{CH}_2\text{OH}):

    • pKa≈15pK_a \approx 15
    • Do not react with either NaOH(aq)\text{NaOH}(aq) or NaHCO3(aq)\text{NaHCO}_3(aq) due to extremely low acidity.
  • Phenols (Ar-OH\text{Ar-OH}), such as Phenol (C6H5OH\text{C}_6\text{H}_5\text{OH}):

    • pKa≈10pK_a \approx 10
    • React with NaOH(aq)\text{NaOH}(aq) to form sodium phenoxide: C6H5OH+NaOH(aq)⟶C6H5O−Na+(aq)+H2O\text{C}_6\text{H}_5\text{OH} + \text{NaOH}(aq) \longrightarrow \text{C}_6\text{H}_5\text{O}^-\text{Na}^+(aq) + \text{H}_2\text{O}
    • Do not react with NaHCO3(aq)\text{NaHCO}_3(aq) because carbonic acid (H2CO3\text{H}_2\text{CO}_3, pKa≈6.37pK_a \approx 6.37) is a stronger acid than phenol.

3. Evaluation of Binary Mixtures

  • Option (A): C6H5OH\mathrm{C_6H_5OH} (Phenol) and C6H5COOH\mathrm{C_6H_5COOH} (Benzoic acid)

    • Treatment with NaOH(aq)\text{NaOH}(aq): Both phenol and benzoic acid react and dissolve in the aqueous phase as sodium salts. They cannot be separated.
    • Incorrect\mathbf{Incorrect}
  • Option (B): C6H5COOH\mathrm{C_6H_5COOH} (Benzoic acid) and C6H5CH2OH\mathrm{C_6H_5CH_2OH} (Benzyl alcohol)

    • Treatment with NaOH(aq)\text{NaOH}(aq): Benzoic acid reacts to form soluble C6H5COO−Na+\text{C}_6\text{H}_5\text{COO}^-\text{Na}^+ (aqueous layer), while benzyl alcohol remains unreacted (organic layer). Separated successfully.
    • Treatment with NaHCO3(aq)\text{NaHCO}_3(aq): Benzoic acid reacts to form soluble C6H5COO−Na+\text{C}_6\text{H}_5\text{COO}^-\text{Na}^+ (aqueous layer), while benzyl alcohol remains unreacted (organic layer). Separated successfully.
    • Correct\mathbf{Correct}
  • Option (C): C6H5CH2OH\mathrm{C_6H_5CH_2OH} (Benzyl alcohol) and C6H5OH\mathrm{C_6H_5OH} (Phenol)

    • Treatment with NaHCO3(aq)\text{NaHCO}_3(aq): Neither compound reacts with NaHCO3\text{NaHCO}_3; both remain together in the organic layer. They cannot be separated using NaHCO3(aq)\text{NaHCO}_3(aq).
    • Incorrect\mathbf{Incorrect}
  • Option (D): C6H5CH2OH\mathrm{C_6H_5CH_2OH} (Benzyl alcohol) and C6H5CH2COOH\mathrm{C_6H_5CH_2COOH} (Phenylacetic acid)

    • Treatment with NaOH(aq)\text{NaOH}(aq): Phenylacetic acid reacts to form soluble C6H5CH2COO−Na+\text{C}_6\text{H}_5\text{CH}_2\text{COO}^-\text{Na}^+ (aqueous layer), while benzyl alcohol remains unreacted (organic layer). Separated successfully.
    • Treatment with NaHCO3(aq)\text{NaHCO}_3(aq): Phenylacetic acid reacts to form soluble C6H5CH2COO−Na+\text{C}_6\text{H}_5\text{CH}_2\text{COO}^-\text{Na}^+ (aqueous layer), while benzyl alcohol remains unreacted (organic layer). Separated successfully.
    • Correct\mathbf{Correct}

Conclusion

The mixtures that satisfy the differential extraction scheme are those in (B) and (D).