JEE Challenger
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Resistance of a Thin Square Conducting Sheet

Consider a thin square sheet of side L\text{L} and thickness t\text{t}, made of a material of resistivity ρ\rho. The resistance between two opposite faces, shown by the shaded areas in the figure is

Diagram 0

Options

A

directly proportional to L\text{L}

B

directly proportional to t\text{t}

C

independent of L\text{L}

Correct
D

independent of t\text{t}

Step-by-Step Solution

To find the resistance between the two opposite shaded faces of the thin square sheet:

  1. Identify the length of the conductor along the direction of current flow:
    The current flows from one shaded face across the sheet to the opposite shaded face. The distance traversed by the current is the length of the side of the square:
    ℓ=L\ell = L

  2. Determine the cross-sectional area perpendicular to the current flow:
    The face through which the current enters (and leaves) has a width of LL and a thickness of tt. Therefore, the cross-sectional area is:
    A=L⋅tA = L \cdot t

  3. Calculate the resistance (RR):
    Using the formula for electrical resistance in terms of resistivity ρ\rho, length ℓ\ell, and cross-sectional area AA:
    R=ρℓA=ρLL⋅t=ρtR = \rho \frac{\ell}{A} = \rho \frac{L}{L \cdot t} = \frac{\rho}{t}

From this result, we see that the resistance R=ρtR = \frac{\rho}{t}:

  • Is inversely proportional to the thickness tt.
  • Is completely independent of the side length LL.

Thus, the resistance is independent of LL.

Correct Option: C