To determine which of the given statements are true, we use the given matrix equation G=(I−EF)−1.
Since G is the inverse of (I−EF), we have:
(I−EF)G=G(I−EF)=I
Expanding both products:
- (I−EF)G=I⟹G−EFG=I⟹EFG=G−I
- G(I−EF)=I⟹G−GEF=I⟹GEF=G−I
Analysis of Option (C):
From the relations above, we have:
EFG=G−IandGEF=G−I
Thus,
EFG=GEF
Hence, Option (C) is TRUE.
Analysis of Option (B):
Consider the expression (I−FE)(I+FGE):
(I−FE)(I+FGE)=I+FGE−FE−FEFGE
Substitute EFG=G−I into the product FEFGE=F(EFG)E:
FEFGE=F(G−I)E=FGE−FE
Substituting this back into the expansion gives:
(I−FE)(I+FGE)=I+FGE−FE−(FGE−FE)=I
Hence, Option (B) is TRUE.
Analysis of Option (A):
Consider the matrix product (I−FE)(FGE):
(I−FE)(FGE)=FGE−FEFGE=FGE−F(EFG)E
Using EFG=G−I:
(I−FE)(FGE)=FGE−F(G−I)E=FGE−(FGE−FE)=FE
Taking the determinant on both sides:
∣FE∣=∣(I−FE)(FGE)∣
Using the property ∣AB∣=∣A∣∣B∣ for any square matrices A and B:
∣FE∣=∣I−FE∣∣FGE∣
Hence, Option (A) is TRUE.
Analysis of Option (D):
Consider the product (I−FE)(I−FGE):
(I−FE)(I−FGE)=I−FGE−FE+FEFGE
Substitute FEFGE=FGE−FE:
(I−FE)(I−FGE)=I−FGE−FE+(FGE−FE)=I−2FE=I
Hence, Option (D) is FALSE.
Conclusion:
The correct statements are (A), (B), and (C).