JEE Challenger
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Properties of Invertible Matrix Products and Identities

For any 3×33 \times 3 matrix MM, let ∣M∣|M| denote the determinant of MM. Let II be the 3×33 \times 3 identity matrix. Consider two 3×33 \times 3 matrices EE and FF such that (I−EF)(I - EF) is invertible. If G=(I−EF)−1G = (I - EF)^{-1}, then which of the following statements is (are) TRUE ?

Options

A

∣FE∣=∣I−FE∣∣FGE∣|FE| = |I - FE||FGE|

Correct
B

(I−FE)(I+FGE)=I(I - FE)(I + FGE) = I

Correct
C

EFG=GEFEFG = GEF

Correct
D

(I−FE)(I−FGE)=I(I - FE)(I - FGE) = I

Step-by-Step Solution

To determine which of the given statements are true, we use the given matrix equation G=(I−EF)−1G = (I - EF)^{-1}.

Since GG is the inverse of (I−EF)(I - EF), we have: (I−EF)G=G(I−EF)=I(I - EF)G = G(I - EF) = I

Expanding both products:

  1. (I−EF)G=I  ⟹  G−EFG=I  ⟹  EFG=G−I(I - EF)G = I \implies G - EFG = I \implies EFG = G - I
  2. G(I−EF)=I  ⟹  G−GEF=I  ⟹  GEF=G−IG(I - EF) = I \implies G - GEF = I \implies GEF = G - I

Analysis of Option (C):

From the relations above, we have: EFG=G−IandGEF=G−IEFG = G - I \quad \text{and} \quad GEF = G - I Thus, EFG=GEFEFG = GEF Hence, Option (C) is TRUE.


Analysis of Option (B):

Consider the expression (I−FE)(I+FGE)(I - FE)(I + FGE): (I−FE)(I+FGE)=I+FGE−FE−FEFGE(I - FE)(I + FGE) = I + FGE - FE - FEFGE

Substitute EFG=G−IEFG = G - I into the product FEFGE=F(EFG)EFEFGE = F(EFG)E: FEFGE=F(G−I)E=FGE−FEFEFGE = F(G - I)E = FGE - FE

Substituting this back into the expansion gives: (I−FE)(I+FGE)=I+FGE−FE−(FGE−FE)=I(I - FE)(I + FGE) = I + FGE - FE - (FGE - FE) = I Hence, Option (B) is TRUE.


Analysis of Option (A):

Consider the matrix product (I−FE)(FGE)(I - FE)(FGE): (I−FE)(FGE)=FGE−FEFGE=FGE−F(EFG)E(I - FE)(FGE) = FGE - FEFGE = FGE - F(EFG)E

Using EFG=G−IEFG = G - I: (I−FE)(FGE)=FGE−F(G−I)E=FGE−(FGE−FE)=FE(I - FE)(FGE) = FGE - F(G - I)E = FGE - (FGE - FE) = FE

Taking the determinant on both sides: ∣FE∣=∣(I−FE)(FGE)∣|FE| = |(I - FE)(FGE)|

Using the property ∣AB∣=∣A∣∣B∣|AB| = |A||B| for any square matrices AA and BB: ∣FE∣=∣I−FE∣∣FGE∣|FE| = |I - FE||FGE| Hence, Option (A) is TRUE.


Analysis of Option (D):

Consider the product (I−FE)(I−FGE)(I - FE)(I - FGE): (I−FE)(I−FGE)=I−FGE−FE+FEFGE(I - FE)(I - FGE) = I - FGE - FE + FEFGE

Substitute FEFGE=FGE−FEFEFGE = FGE - FE: (I−FE)(I−FGE)=I−FGE−FE+(FGE−FE)=I−2FE≠I(I - FE)(I - FGE) = I - FGE - FE + (FGE - FE) = I - 2FE \neq I Hence, Option (D) is FALSE.


Conclusion:

The correct statements are (A), (B), and (C).