Properties and Reactions of Xenon Fluoride Compounds

To determine the correct statement(s), we first identify the compounds $\text{P}$, $\text{Q}$, and $\text{R}$ based on the given chemical reactions:

1. Identification of Compound $\text{P}$: When xenon ($\text{Xe}$) and fluorine ($\text{F}_2$) are mixed in a $1:5$ molar ratio at $873\text{ K}$ and $7\text{ bar}$, xenon tetrafluoride ($\text{XeF}_4$) is formed: $\text{Xe(g)} + 2\text{F}_2\text{(g)} \xrightarrow{873\text{ K, } 7\text{ bar}} \text{XeF}_4\text{(s)}$ Therefore, compound $\text{P}$ is $\text{XeF}_4$.

2. Identification of Compound $\text{Q}$: The reaction of $\text{XeF}_4$ ($\text{P}$) with dioxygen difluoride ($\text{O}_2\text{F}_2$) at $143\text{ K}$ yields xenon hexafluoride ($\text{XeF}_6$): $\text{XeF}_4 + \text{O}_2\text{F}_2 \xrightarrow{143\text{ K}} \text{XeF}_6 + \text{O}_2$ Therefore, compound $\text{Q}$ is $\text{XeF}_6$.

3. Identification of Compound $\text{R}$: Complete hydrolysis of $\text{XeF}_6$ ($\text{Q}$) produces xenon trioxide ($\text{XeO}_3$) and hydrofluoric acid ($\text{HF}$): $\text{XeF}_6 + 3\text{H}_2\text{O} \xrightarrow{\text{complete hydrolysis}} \text{XeO}_3 + 6\text{HF}$ Therefore, compound $\text{R}$ is $\text{XeO}_3$.

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Evaluation of Options:

• Option (A): In $\text{XeF}_4$ ($\text{P}$), the central xenon ($\text{Xe}$) atom has $8$ valence electrons. It forms $4$ single bonds with four fluorine atoms, leaving $8 - 4 = 4$ non-bonding electrons, which correspond to two lone pairs. Thus, option (A) is correct.

• Option (B): In $\text{XeF}_6$ ($\text{Q}$), the central xenon atom has $6$ bond pairs and $1$ lone pair ($sp^3d^3$ hybridization). Consequently, its molecular geometry is a distorted octahedral structure, not a perfect octahedron. Thus, option (B) is incorrect.

• Option (C): Xenon fluorides ($\text{XeF}_2$, $\text{XeF}_4$, and $\text{XeF}_6$) act as strong fluorinating agents capable of transferring fluorine to other species. Thus, option (C) is correct.

• Option (D): In $\text{XeO}_3$ ($\text{R}$), xenon forms $3$ double bonds with oxygen atoms ($\text{Xe}=\text{O}$) and possesses $1$ lone pair. With a steric number of $4$ ($sp^3$ hybridized), the molecular shape is trigonal pyramidal. Thus, option (D) is correct.

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Conclusion:

The correct statements are A, C, and D.