JEE Challenger
More from General Principles and Processes of Isolation of Elements

Oxidation States of Iron in Haematite and Magnetite

Oxidation states of the metal in the minerals haematite and magnetite, respectively, are

Options

A

II, III in haematite and III in magnetite

B

II, III in haematite and II in magnetite

C

II in haematite and II, III in magnetite

D

III in haematite and II, III in magnetite

Correct

Step-by-Step Solution

To determine the oxidation states of iron in the minerals haematite and magnetite:

  1. Haematite:

    • The chemical formula of haematite is Fe2O3\mathrm{Fe}_2\mathrm{O}_3.
    • Oxygen typically has an oxidation state of −2-2.
    • Let the oxidation state of iron (Fe\mathrm{Fe}) in haematite be xx.
    • Applying the rule of electroneutrality for the compound:
      2x+3(−2)=02x + 3(-2) = 0
      2x−6=0  ⟹  x=+3 (or III)2x - 6 = 0 \implies x = +3 \text{ (or } \mathrm{III}\text{)}
    • Thus, iron is present solely in the III\mathrm{III} oxidation state in haematite.
  2. Magnetite:

    • The chemical formula of magnetite is Fe3O4\mathrm{Fe}_3\mathrm{O}_4.
    • Magnetite is a mixed oxide composed of iron(II) oxide and iron(III) oxide in a 1:11:1 stoichiometric ratio:
      Fe3O4≡FeO⋅Fe2O3\mathrm{Fe}_3\mathrm{O}_4 \equiv \mathrm{FeO} \cdot \mathrm{Fe}_2\mathrm{O}_3
    • In FeO\mathrm{FeO}:
      x+(−2)=0  ⟹  x=+2 (or II)x + (-2) = 0 \implies x = +2 \text{ (or } \mathrm{II}\text{)}
    • In Fe2O3\mathrm{Fe}_2\mathrm{O}_3:
      2x+3(−2)=0  ⟹  x=+3 (or III)2x + 3(-2) = 0 \implies x = +3 \text{ (or } \mathrm{III}\text{)}
    • Consequently, each formula unit of magnetite contains one Fe2+\mathrm{Fe}^{2+} ion and two Fe3+\mathrm{Fe}^{3+} ions. Therefore, iron exhibits both II\mathrm{II} and III\mathrm{III} oxidation states in magnetite.

Hence, the oxidation states of the metal in haematite and magnetite are III\mathrm{III} and II,III\mathrm{II, III}, respectively.

Correct Option: (D)

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