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Osmotic Pressure Comparison and Solution Hypotonicity Across Semi Permeable Membrane

At 27C27\,^{\circ}\text{C}, 0.1 M0.1\text{ M}, 1 L1\text{ L} K4[Fe(CN)6]\text{K}_4[\text{Fe}(\text{CN})_6] aqueous solution and 0.1 M0.1\text{ M}, 1 L1\text{ L} FeCl3\text{FeCl}_3 aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct?

Question Diagram 1

Options

A

Blue color is formed on both sides.

B

Ionic solutes in aqueous solution can pass through semi-permeable membrane.

C

Solution on side 'y' is hypotonic.

Correct
D

To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side 'x'.

Topics & Concepts

Step-by-Step Solution

To determine the correct statement, let us analyze the colligative properties (specifically osmotic pressure) of the solutions on both sides of the semi-permeable membrane.

1. Side 'x' (K4[Fe(CN)6]\text{K}_4[\text{Fe}(\text{CN})_6] solution):

  • Concentration, Cx=0.1 MC_x = 0.1\text{ M}
  • Dissociation equation for K4[Fe(CN)6]\text{K}_4[\text{Fe}(\text{CN})_6]: K4[Fe(CN)6] (aq)4K+(aq)+[Fe(CN)6]4(aq)\text{K}_4[\text{Fe}(\text{CN})_6]\text{ (aq)} \rightarrow 4\text{K}^+\text{(aq)} + [\text{Fe}(\text{CN})_6]^{4-}\text{(aq)}
  • Since dissociation is complete, the van 't Hoff factor is: ix=1+(51)×1=5i_x = 1 + (5 - 1) \times 1 = 5
  • Total effective ion concentration on side 'x': Ceff,x=ix×Cx=5×0.1 M=0.5 MC_{\text{eff}, x} = i_x \times C_x = 5 \times 0.1\text{ M} = 0.5\text{ M}
  • Osmotic pressure of side 'x': Πx=ixCxRT=0.5RT\Pi_x = i_x C_x R T = 0.5 R T

2. Side 'y' (FeCl3\text{FeCl}_3 solution):

  • Concentration, Cy=0.1 MC_y = 0.1\text{ M}
  • Dissociation equation for FeCl3\text{FeCl}_3: FeCl3 (aq)Fe3+(aq)+3Cl(aq)\text{FeCl}_3\text{ (aq)} \rightarrow \text{Fe}^{3+}\text{(aq)} + 3\text{Cl}^-\text{(aq)}
  • Since dissociation is complete, the van 't Hoff factor is: iy=1+(41)×1=4i_y = 1 + (4 - 1) \times 1 = 4
  • Total effective ion concentration on side 'y': Ceff,y=iy×Cy=4×0.1 M=0.4 MC_{\text{eff}, y} = i_y \times C_y = 4 \times 0.1\text{ M} = 0.4\text{ M}
  • Osmotic pressure of side 'y': Πy=iyCyRT=0.4RT\Pi_y = i_y C_y R T = 0.4 R T

3. Analysis of Options:

  • Comparison of Osmotic Pressures: Πx=0.5RT>Πy=0.4RT\Pi_x = 0.5 RT > \Pi_y = 0.4 RT Since the osmotic pressure of the solution on side 'y' (Πy\Pi_y) is lower than that on side 'x' (Πx\Pi_x), the solution on side 'y' is hypotonic relative to side 'x' (and side 'x' is hypertonic relative to side 'y'). Therefore, Statement C is correct.

  • Option A: A semi-permeable membrane (SPM) allows only solvent (water) molecules to pass through, preventing solute ions (Fe3+\text{Fe}^{3+} and [Fe(CN)6]4[\text{Fe}(\text{CN})_6]^{4-}) from crossing. Thus, no complexation occurs, and no blue color is formed.

  • Option B: Solute ions cannot pass through a semi-permeable membrane.

  • Option D: To cause reverse osmosis, an external pressure greater than the net osmotic pressure difference (ΔΠ=ΠxΠy\Delta \Pi = \Pi_x - \Pi_y) must be applied to the hypertonic side (side 'x'), not just "any value".

Thus, the correct option is C.

Osmotic Pressure Comparison and Solution Hypotonicity Across Semi Permeable Membrane | Chemistry PYQ Solution - JEE Challenger