Osmotic Pressure Comparison and Solution Hypotonicity Across Semi Permeable Membrane
At , , aqueous solution and , aqueous solution are placed in a container separated by a semi permeable membrane AB. Assume complete dissociation of both the solutes. Which of the following statement is correct?

Options
Blue color is formed on both sides.
Ionic solutes in aqueous solution can pass through semi-permeable membrane.
Solution on side 'y' is hypotonic.
To cause the reverse flow of solvent during osmosis, external pressure (any value) should be applied to side 'x'.
Topics & Concepts
Step-by-Step Solution
To determine the correct statement, let us analyze the colligative properties (specifically osmotic pressure) of the solutions on both sides of the semi-permeable membrane.
1. Side 'x' ( solution):
- Concentration,
- Dissociation equation for :
- Since dissociation is complete, the van 't Hoff factor is:
- Total effective ion concentration on side 'x':
- Osmotic pressure of side 'x':
2. Side 'y' ( solution):
- Concentration,
- Dissociation equation for :
- Since dissociation is complete, the van 't Hoff factor is:
- Total effective ion concentration on side 'y':
- Osmotic pressure of side 'y':
3. Analysis of Options:
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Comparison of Osmotic Pressures: Since the osmotic pressure of the solution on side 'y' () is lower than that on side 'x' (), the solution on side 'y' is hypotonic relative to side 'x' (and side 'x' is hypertonic relative to side 'y'). Therefore, Statement C is correct.
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Option A: A semi-permeable membrane (SPM) allows only solvent (water) molecules to pass through, preventing solute ions ( and ) from crossing. Thus, no complexation occurs, and no blue color is formed.
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Option B: Solute ions cannot pass through a semi-permeable membrane.
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Option D: To cause reverse osmosis, an external pressure greater than the net osmotic pressure difference () must be applied to the hypertonic side (side 'x'), not just "any value".
Thus, the correct option is C.