JEE Challenger
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Number of Hydroxyl Groups in Hydrogenated and Hydroxylated Major Product

Determine the total number of hydroxyl groups present in a molecule of the major product P\mathbf{P} obtained from the following reaction sequence:

Question Diagram 1
Official Numerical Answer6

Step-by-Step Solution

To find the total number of hydroxyl groups present in a molecule of the major product P\mathbf{P}, we analyze the two steps of the reaction sequence:

  1. Step 1: Selective Hydrogenation using Lindlar's Catalyst Reagents: H2, Pd-BaSO4, quinoline\text{Reagents: } \text{H}_2, \, \text{Pd-BaSO}_4, \, \text{quinoline} Lindlar's catalyst selectively reduces alkynes to (Z)(Z)-alkenes (cis-alkenes) without reducing the existing carbon-carbon double bonds (C=C\text{C}=\text{C}) in the molecule.

    • The reactant has one internal alkyne group (−C≡C−-\text{C}\equiv\text{C}-) and two alkene double bonds (one in the cyclopentenyl ring and one in the cyclohexenyl ring).
    • Therefore, the alkyne is stereoselectively reduced to a cis-alkene: −C≡C−→H2, Pd-BaSO4, quinoline−CH=CH−-\text{C}\equiv\text{C}- \xrightarrow{\text{H}_2, \, \text{Pd-BaSO}_4, \, \text{quinoline}} -\text{CH}=\text{CH}-
    • After this step, the intermediate contains a total of 33 carbon-carbon double bonds:
      • 11 in the 5-membered ring
      • 11 in the acyclic chain (formed from the alkyne)
      • 11 in the 6-membered ring
  2. Step 2: Dihydroxylation using Baeyer's Reagent Reagents: dil. KMnO4 (excess), 273 K\text{Reagents: } \text{dil. } \text{KMnO}_4 \text{ (excess)}, \, 273\text{ K} Cold, dilute alkaline KMnO4\text{KMnO}_4 (Baeyer's reagent) carries out syn-dihydroxylation across carbon-carbon double bonds, converting each C=C\text{C}=\text{C} bond into a vicinal diol (adding 22 hydroxyl groups per double bond): −CH=CH−→dil. KMnO4, 273 K−CH(OH)−CH(OH)−-\text{CH}=\text{CH}- \xrightarrow{\text{dil. } \text{KMnO}_4, \, 273\text{ K}} -\text{CH(OH)}-\text{CH(OH)}- Since KMnO4\text{KMnO}_4 is present in excess, all 33 double bonds undergo dihydroxylation: Total number of hydroxyl (−OH) groups=3×2=6\text{Total number of hydroxyl } (-\text{OH}) \text{ groups} = 3 \times 2 = 6

Therefore, the total number of hydroxyl groups present in a molecule of the major product P\mathbf{P} is 6.