Monatomic Ideal Gas Thermodynamic Cycle in TV Diagram
One mole of a monatomic ideal gas undergoes a cyclic thermodynamic process as represented in the accompanying - diagram, where denotes the volume and denotes the temperature. Which of the following statements is (are) correct?

Options
Process I corresponds to an isochoric process
In process II, heat is absorbed by the gas
In process IV, heat is released by the gas
Processes I and III are not isobaric
Topics & Concepts
Step-by-Step Solution
To determine the correct statements for the given thermodynamic cycle of an ideal gas in the - plane:
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Process I: The volume changes as temperature varies, meaning the process cannot be isochoric. Therefore, statement (A) is incorrect.
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Processes I and III: For an isobaric process, Charles's law requires , which represents a straight line passing through the origin with a positive slope. Since neither Process I nor Process III follows this relation, neither process is isobaric. Therefore, statement (D) is correct.
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Process II: This is an isothermal expansion at constant temperature () with increasing volume (). Since and work done , the first law of thermodynamics gives . Thus, heat is absorbed by the gas, making statement (B) correct.
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Process IV: This is an isothermal compression at constant temperature () with decreasing volume (). With and work done , the first law yields . Thus, heat is released by the gas, making statement (C) correct.
Hence, the correct statements are (B), (C), and (D).