JEE Challenger
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Molecules Following Octet Rule in Chemistry Sets

The option(s) in which at least three molecules follow Octet Rule is(are)

Options

A

CO2\text{CO}_2, C2H4\text{C}_2\text{H}_4, NO\text{NO} and HCl\text{HCl}

Correct
B

NO2\text{NO}_2, O3\text{O}_3, HCl\text{HCl} and H2SO4\text{H}_2\text{SO}_4

C

BCl3\text{BCl}_3, NO\text{NO}, NO2\text{NO}_2 and H2SO4\text{H}_2\text{SO}_4

D

CO2\text{CO}_2, BCl3\text{BCl}_3, O3\text{O}_3 and C2H4\text{C}_2\text{H}_4

Correct

Step-by-Step Solution

To determine which options contain at least three molecules that follow the octet rule, let us analyze the electronic configuration and octet status of each given molecule:

  1. Definition of Octet Rule and Exceptions:
    • Octet Rule: Atoms gain, lose, or share electrons to achieve a valence shell containing eight electrons (8e8\, e^-).
    • Incomplete Octet (Electron-deficient species): Molecules where the central atom has fewer than 8 valence electrons (e.g., BCl3\text{BCl}_3, which has 6e6\, e^- around B\text{B}).
    • Odd-Electron Molecules: Species with an odd number of total valence electrons, where at least one atom cannot achieve 8 valence electrons (e.g., NO\text{NO} and NO2\text{NO}_2, where N\text{N} has 7e7\, e^-).
    • Expanded Octet (Hypervalent species): Molecules where the central atom expands its octet to hold more than 8 electrons (e.g., H2SO4\text{H}_2\text{SO}_4, where S\text{S} has 12e12\, e^- in its valence shell).

  1. Analysis of Individual Molecules:

    • CO2\text{CO}_2: The Lewis structure is O=C=O\text{O}=\text{C}=\text{O}.

      • Central C\text{C} atom forms 2 double bonds     4×2=8e\implies 4 \times 2 = 8\, e^-.
      • Each O\text{O} atom has 2 lone pairs and 1 double bond     8e\implies 8\, e^-.
      • Follows octet rule.
    • C2H4\text{C}_2\text{H}_4: The Lewis structure is H2C=CH2\text{H}_2\text{C}=\text{CH}_2.

      • Each C\text{C} atom forms 2 single bonds with H\text{H} and 1 double bond with C    8e\text{C} \implies 8\, e^-.
      • Follows octet rule.
    • HCl\text{HCl}: The Lewis structure is HCl\text{H}-\text{Cl}.

      • Cl\text{Cl} has 3 lone pairs and 1 single bond     8e\implies 8\, e^-.
      • Follows octet rule.
    • O3\text{O}_3: The Lewis structure is a resonance hybrid (O=O+O\text{O}=\text{O}^+-\text{O}^-).

      • Central O\text{O} has 1 double bond, 1 single bond, and 1 lone pair     8e\implies 8\, e^-.
      • Terminal oxygens also complete their octets.
      • Follows octet rule.
    • NO\text{NO}: Total valence electrons = 5(N)+6(O)=115 (\text{N}) + 6 (\text{O}) = 11 (odd electron species).

      • N\text{N} has only 7e7\, e^- around it.
      • Does NOT follow octet rule.
    • NO2\text{NO}_2: Total valence electrons = 5(N)+2×6(O)=175 (\text{N}) + 2 \times 6 (\text{O}) = 17 (odd electron species).

      • N\text{N} has only 7e7\, e^- around it.
      • Does NOT follow octet rule.
    • BCl3\text{BCl}_3: Central B\text{B} forms 3 single bonds with Cl\text{Cl} atoms.

      • B\text{B} has 3×2=6e3 \times 2 = 6\, e^- (incomplete octet).
      • Does NOT follow octet rule.
    • H2SO4\text{H}_2\text{SO}_4: Central S\text{S} forms 2 single bonds (SOH\text{S}-\text{OH}) and 2 double bonds (S=O\text{S}=\text{O}).

      • S\text{S} has 6×2=12e6 \times 2 = 12\, e^- (expanded octet).
      • Does NOT follow octet rule.

  1. Evaluating the Options:

    • Option (A): CO2\text{CO}_2, C2H4\text{C}_2\text{H}_4, NO\text{NO} and HCl\text{HCl}

      • CO2\text{CO}_2 (Yes), C2H4\text{C}_2\text{H}_4 (Yes), NO\text{NO} (No), HCl\text{HCl} (Yes)
      • Number of molecules following octet rule = 33
      • Option (A) is correct.
    • Option (B): NO2\text{NO}_2, O3\text{O}_3, HCl\text{HCl} and H2SO4\text{H}_2\text{SO}_4

      • NO2\text{NO}_2 (No), O3\text{O}_3 (Yes), HCl\text{HCl} (Yes), H2SO4\text{H}_2\text{SO}_4 (No)
      • Number of molecules following octet rule = 22
      • Option (B) is incorrect.
    • Option (C): BCl3\text{BCl}_3, NO\text{NO}, NO2\text{NO}_2 and H2SO4\text{H}_2\text{SO}_4

      • BCl3\text{BCl}_3 (No), NO\text{NO} (No), NO2\text{NO}_2 (No), H2SO4\text{H}_2\text{SO}_4 (No)
      • Number of molecules following octet rule = 00
      • Option (C) is incorrect.
    • Option (D): CO2\text{CO}_2, BCl3\text{BCl}_3, O3\text{O}_3 and C2H4\text{C}_2\text{H}_4

      • CO2\text{CO}_2 (Yes), BCl3\text{BCl}_3 (No), O3\text{O}_3 (Yes), C2H4\text{C}_2\text{H}_4 (Yes)
      • Number of molecules following octet rule = 33
      • Option (D) is correct.

Correct Options: (A) and (D)