JEE Challenger
More from Circles

Matching Geometric Curves with Common Tangents and Normals

Match the statements in Column I with the properties in Column II and indicate your answer by darkening the appropriate bubbles in the 4×44 \times 4 matrix given in the ORS.

Column IColumn II(A) Two intersecting circles(p) have a common tangent(B) Two mutually external circles(q) have a common normal(C) Two circles, one strictly inside the other(r) do not have a common tangent(D) Two branches of a hyperbola(s) do not have a common normal\begin{array}{ll} \textbf{Column I} & \textbf{Column II} \\[6pt] \text{(A) Two intersecting circles} & \text{(p) have a common tangent} \\[6pt] \text{(B) Two mutually external circles} & \text{(q) have a common normal} \\[6pt] \text{(C) Two circles, one strictly inside the other} & \text{(r) do not have a common tangent} \\[6pt] \text{(D) Two branches of a hyperbola} & \text{(s) do not have a common normal} \end{array}

Options

A

(A)→(p),  (B)→(p,q),  (C)→(r),  (D)→(q,s)(\text{A}) \rightarrow (\text{p}),\; (\text{B}) \rightarrow (\text{p}, \text{q}),\; (\text{C}) \rightarrow (\text{r}),\; (\text{D}) \rightarrow (\text{q}, \text{s})

B

(A)→(p,q),  (B)→(p),  (C)→(q,s),  (D)→(r)(\text{A}) \rightarrow (\text{p}, \text{q}),\; (\text{B}) \rightarrow (\text{p}),\; (\text{C}) \rightarrow (\text{q}, \text{s}),\; (\text{D}) \rightarrow (\text{r})

C

(A)→(p),  (B)→(q),  (C)→(q,r),  (D)→(s)(\text{A}) \rightarrow (\text{p}),\; (\text{B}) \rightarrow (\text{q}),\; (\text{C}) \rightarrow (\text{q}, \text{r}),\; (\text{D}) \rightarrow (\text{s})

D

(A)→(p,q),  (B)→(p,q),  (C)→(q,r),  (D)→(q,r)(\text{A}) \rightarrow (\text{p}, \text{q}),\; (\text{B}) \rightarrow (\text{p}, \text{q}),\; (\text{C}) \rightarrow (\text{q}, \text{r}),\; (\text{D}) \rightarrow (\text{q}, \text{r})

Correct

Step-by-Step Solution

Geometric Analysis of Configurations:

  1. (A) Two intersecting circles:
  • They have two direct common tangents, so they have a common tangent (pp).
  • Any normal to a circle passes through its center. The straight line joining the centers of the two circles is a normal to both circles simultaneously. Hence, they have a common normal (qq).
  • Matching: (A)→(p,q)(\text{A}) \rightarrow (\text{p}, \text{q}).
  1. (B) Two mutually external circles:
  • They have four common tangents (two direct, two transverse), so they have a common tangent (pp).
  • The line of centers is a normal to both circles, so they have a common normal (qq).
  • Matching: (B)→(p,q)(\text{B}) \rightarrow (\text{p}, \text{q}).
  1. (C) Two circles, one strictly inside the other:
  • One circle is entirely contained within the interior of the other without touching, so they do not have a common tangent (rr).
  • The line connecting their centers passes through the center of both circles and is perpendicular to both circumferences, so they have a common normal (qq).
  • Matching: (C)→(q,r)(\text{C}) \rightarrow (\text{q}, \text{r}).
  1. (D) Two branches of a hyperbola:
  • No tangent to one branch can touch the other branch (hyperbolic tangents lie strictly on their respective branches), so they do not have a common tangent (rr).
  • The transverse axis is the axis of symmetry and intersects both vertices perpendicularly, serving as a shared normal to both branches. Hence, they have a common normal (qq).
  • Matching: (D)→(q,r)(\text{D}) \rightarrow (\text{q}, \text{r}).

Matching:
(A)→(p,q),  (B)→(p,q),  (C)→(q,r),  (D)→(q,r)(\text{A}) \rightarrow (\text{p}, \text{q}),\; (\text{B}) \rightarrow (\text{p}, \text{q}),\; (\text{C}) \rightarrow (\text{q}, \text{r}),\; (\text{D}) \rightarrow (\text{q}, \text{r})

Correct Answer: D