JEE Challenger

Matching Anionic Species with Corresponding Ores

Pair the anionic species listed in Column I with the corresponding ore(s) in Column II.

Column IColumn II(A) Carbonate(P) Siderite(B) Sulphide(Q) Malachite(C) Hydroxide(R) Bauxite(D) Oxide(S) Calamine(T) Argentite\begin{array}{ll} \textbf{Column I} & \textbf{Column II} \\ \text{(A) Carbonate} & \text{(P) Siderite} \\ \text{(B) Sulphide} & \text{(Q) Malachite} \\ \text{(C) Hydroxide} & \text{(R) Bauxite} \\ \text{(D) Oxide} & \text{(S) Calamine} \\ & \text{(T) Argentite} \end{array}

Step-by-Step Solution

To match the anionic species given in Column I with the corresponding ores in Column II, we first determine the chemical formula and constituent anions of each ore listed in Column II:

  1. (P) Siderite: Chemical formula: FeCO3\text{FeCO}_3 Contains: Carbonate ion (CO32−\text{CO}_3^{2-}). Matches with: (A)

  2. (Q) Malachite: Chemical formula: CuCO3⋅Cu(OH)2\text{CuCO}_3 \cdot \text{Cu(OH)}_2 Contains: Carbonate ion (CO32−\text{CO}_3^{2-}) and Hydroxide ion (OH−\text{OH}^-). Matches with: (A), (C)

  3. (R) Bauxite: Chemical formula: Al2O3⋅xH2O\text{Al}_2\text{O}_3 \cdot x\text{H}_2\text{O} or AlOx(OH)3−2x\text{AlO}_x(\text{OH})_{3-2x} (primarily consisting of minerals such as gibbsite Al(OH)3\text{Al(OH)}_3, boehmite γ-AlO(OH)\gamma\text{-AlO(OH)}, and diaspore α-AlO(OH)\alpha\text{-AlO(OH)}). Contains: Hydroxide ion (OH−\text{OH}^-) and Oxide ion (O2−\text{O}^{2-}). Matches with: (C), (D)

  4. (S) Calamine: Chemical formula: ZnCO3\text{ZnCO}_3 Contains: Carbonate ion (CO32−\text{CO}_3^{2-}). Matches with: (A)

  5. (T) Argentite: Chemical formula: Ag2S\text{Ag}_2\text{S} Contains: Sulphide ion (S2−\text{S}^{2-}). Matches with: (B)


Final Matching:

  • (A) Carbonate (CO32−\text{CO}_3^{2-}) matches with (P), (Q), (S)
  • (B) Sulphide (S2−\text{S}^{2-}) matches with (T)
  • (C) Hydroxide (OH−\text{OH}^-) matches with (Q), (R)
  • (D) Oxide (O2−\text{O}^{2-}) matches with (R)