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Match Physical Quantities with Dimensional Formulas in Modern Physics

Match the LIST-I with LIST-II

List-IList-IIA. Planck’s constantI. ML2T2B. Stopping potentialII. T1C. Work functionIII. ML2T1D. Threshold frequencyIV. ML2T3A1\begin{array}{|l|l|} \hline \text{List-I} & \text{List-II} \\ \hline \text{A. Planck's constant} & \text{I. } \text{M}\text{L}^2\text{T}^{-2} \\ \hline \text{B. Stopping potential} & \text{II. } \text{T}^{-1} \\ \hline \text{C. Work function} & \text{III. } \text{M}\text{L}^2\text{T}^{-1} \\ \hline \text{D. Threshold frequency} & \text{IV. } \text{M}\text{L}^2\text{T}^{-3}\text{A}^{-1} \\ \hline \end{array}

Choose the correct answer from the options given below:

Options

A

A-III, B-IV, C-I, D-II

Correct
B

A-I, B-II, C-III, D-IV

C

A-IV, B-III, C-I, D-II

D

A-I, B-IV, C-III, D-II

Step-by-Step Solution

To determine the correct matching between the physical quantities in List-I and their dimensional formulas in List-II, we derive the dimensions of each quantity as follows:

  1. Planck's constant (hh): Using the energy equation for a photon: E=hν    h=EνE = h\nu \implies h = \frac{E}{\nu} where EE is energy and ν\nu is frequency.

    • Dimension of Energy [E]=[ML2T2][E] = [\text{M}\text{L}^2\text{T}^{-2}]
    • Dimension of Frequency [ν]=[T1][\nu] = [\text{T}^{-1}]

    Thus, the dimension of Planck's constant is: [h]=ML2T2T1=ML2T1[h] = \frac{\text{M}\text{L}^2\text{T}^{-2}}{\text{T}^{-1}} = \text{M}\text{L}^2\text{T}^{-1} Therefore, A matches with III.

  2. Stopping potential (V0V_0): Electric potential is defined as potential energy per unit charge: V0=WqV_0 = \frac{W}{q} where WW is work (energy) and qq is electric charge (q=Itq = I \cdot t).

    • Dimension of Work [W]=[ML2T2][W] = [\text{M}\text{L}^2\text{T}^{-2}]
    • Dimension of Charge [q]=[AT][q] = [\text{A}\text{T}]

    Thus, the dimension of stopping potential is: [V0]=ML2T2AT=ML2T3A1[V_0] = \frac{\text{M}\text{L}^2\text{T}^{-2}}{\text{A}\text{T}} = \text{M}\text{L}^2\text{T}^{-3}\text{A}^{-1} Therefore, B matches with IV.

  3. Work function (ϕ\phi): The work function represents the minimum energy required to liberate an electron from the metal surface. Hence, its dimension is equal to the dimension of energy: [ϕ]=ML2T2[\phi] = \text{M}\text{L}^2\text{T}^{-2} Therefore, C matches with I.

  4. Threshold frequency (ν0\nu_0): Frequency is defined as the reciprocal of time period: ν0=1T\nu_0 = \frac{1}{T}

    Thus, the dimension of threshold frequency is: [ν0]=T1[\nu_0] = \text{T}^{-1} Therefore, D matches with II.

Comparing our results with the given options: A-III, B-IV, C-I, D-II\text{A-III, B-IV, C-I, D-II}

This corresponds to Option A.

Match Physical Quantities with Dimensional Formulas in Modern Physics | Physics PYQ Solution - JEE Challenger