JEE Challenger
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Match Atomic Orbitals with Radial and Nodal Planes

Match the LIST-I with LIST-II

List-IList-IIOrbitalRadial nodes and nodal planeA.2sI.1 Radial node+two nodal planesB.3sII.1 Radial node+one nodal planeC.3pIII.2 Radial nodes+No nodal planeD.4dIV.1 Radial node+No nodal plane\begin{array}{|l|l|l|l|} \hline & \text{List-I} & & \text{List-II} \\ & \text{Orbital} & & \text{Radial nodes and nodal plane} \\ \hline \text{A.} & 2s & \text{I.} & 1 \text{ Radial node} + \text{two nodal planes} \\ \hline \text{B.} & 3s & \text{II.} & 1 \text{ Radial node} + \text{one nodal plane} \\ \hline \text{C.} & 3p & \text{III.} & 2 \text{ Radial nodes} + \text{No nodal plane} \\ \hline \text{D.} & 4d & \text{IV.} & 1 \text{ Radial node} + \text{No nodal plane} \\ \hline \end{array}

Choose the correct answer from the options given below:

Options

A

A-IV, B-I, C-III, D-II

B

A-IV, B-II, C-III, D-I

C

A-III, B-I, C-IV, D-II

D

A-IV, B-III, C-II, D-I

Correct

Topics & Concepts

Step-by-Step Solution

To determine the correct matching between the orbitals in List-I and their corresponding nodes in List-II, we use the standard formulas for the radial nodes and angular nodes (nodal planes) of an atomic orbital:

  1. Number of radial nodes =nl1= n - l - 1
  2. Number of angular nodes (nodal planes) =l= l

where nn is the principal quantum number and ll is the azimuthal quantum number (l=0l = 0 for ss-orbital, l=1l = 1 for pp-orbital, l=2l = 2 for dd-orbital).


Step-by-step Evaluation:

  1. Orbital A: 2s2s

    • n=2,l=0n = 2, \, l = 0
    • Radial nodes =201=1= 2 - 0 - 1 = 1
    • Nodal planes =l=0= l = 0 (No nodal plane)
    • Matching: A \rightarrow IV (1 Radial node+No nodal plane1\text{ Radial node} + \text{No nodal plane})
  2. Orbital B: 3s3s

    • n=3,l=0n = 3, \, l = 0
    • Radial nodes =301=2= 3 - 0 - 1 = 2
    • Nodal planes =l=0= l = 0 (No nodal plane)
    • Matching: B \rightarrow III (2 Radial nodes+No nodal plane2\text{ Radial nodes} + \text{No nodal plane})
  3. Orbital C: 3p3p

    • n=3,l=1n = 3, \, l = 1
    • Radial nodes =311=1= 3 - 1 - 1 = 1
    • Nodal planes =l=1= l = 1 (one nodal plane)
    • Matching: C \rightarrow II (1 Radial node+one nodal plane1\text{ Radial node} + \text{one nodal plane})
  4. Orbital D: 4d4d

    • n=4,l=2n = 4, \, l = 2
    • Radial nodes =421=1= 4 - 2 - 1 = 1
    • Nodal planes =l=2= l = 2 (two nodal planes)
    • Matching: D \rightarrow I (1 Radial node+two nodal planes1\text{ Radial node} + \text{two nodal planes})

Conclusion:

The correct matching combination is: A-IV, B-III, C-II, D-I\text{A-IV, B-III, C-II, D-I}

Hence, the correct option is D.

Match Atomic Orbitals with Radial and Nodal Planes | Chemistry PYQ Solution - JEE Challenger