JEE Challenger
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Locus of Point Dividing Line Segment from Origin to Parabola

Let (x,y)(x, y) be any point on the parabola y2=4xy^2 = 4x. Let PP be the point that divides the line segment from (0,0)(0, 0) to (x,y)(x, y) in the ratio 1:31:3. Then the locus of PP is

Options

A

x2=yx^2 = y

B

y2=2xy^2 = 2x

C

y2=xy^2 = x

Correct
D

x2=2yx^2 = 2y

Topics & Concepts

Step-by-Step Solution

To find the locus of the point PP, let the coordinates of PP be (h,k)(h, k).

Let the origin be O(0,0)O(0, 0) and the point on the parabola be Q(x,y)Q(x, y).

Since the point P(h,k)P(h, k) divides the directed line segment from O(0,0)O(0, 0) to Q(x,y)Q(x, y) in the ratio 1:31 : 3, using the section formula, we have:
h=1⋅x+3⋅01+3=x4  ⟹  x=4hh = \frac{1 \cdot x + 3 \cdot 0}{1 + 3} = \frac{x}{4} \implies x = 4h
k=1⋅y+3⋅01+3=y4  ⟹  y=4kk = \frac{1 \cdot y + 3 \cdot 0}{1 + 3} = \frac{y}{4} \implies y = 4k

The point Q(x,y)Q(x, y) lies on the parabola given by:
y2=4xy^2 = 4x

Substituting x=4hx = 4h and y=4ky = 4k into the equation of the parabola:
(4k)2=4(4h)(4k)^2 = 4(4h)
16k2=16h16k^2 = 16h
k2=hk^2 = h

Replacing (h,k)(h, k) with (x,y)(x, y) gives the locus of PP:
y2=xy^2 = x

Therefore, the correct option is C.