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Infinitely Many Solutions of Linear Equations System

If the system of equations: x+y+z=5x + y + z = 5 x+2y+3z=9x + 2y + 3z = 9 x+3y+λz=μx + 3y + \lambda z = \mu has infinitely many solutions, then the value of λ+μ\lambda + \mu is:

Options

A

16

B

18

Correct
C

19

D

21

Topics & Concepts

Step-by-Step Solution

To find the value of λ+μ\lambda + \mu for which the system of equations has infinitely many solutions, we can write the given system in augmented matrix form [AB][A | B]:

[1115123913λμ]\begin{bmatrix} 1 & 1 & 1 & | & 5 \\ 1 & 2 & 3 & | & 9 \\ 1 & 3 & \lambda & | & \mu \end{bmatrix}

We apply elementary row operations to transform the matrix into row echelon form:

  1. Perform R2R2R1R_2 \to R_2 - R_1 and R3R3R1R_3 \to R_3 - R_1:
[1115012402λ1μ5]\begin{bmatrix} 1 & 1 & 1 & | & 5 \\ 0 & 1 & 2 & | & 4 \\ 0 & 2 & \lambda - 1 & | & \mu - 5 \end{bmatrix}
  1. Perform R3R32R2R_3 \to R_3 - 2R_2:
[1115012400λ5μ13]\begin{bmatrix} 1 & 1 & 1 & | & 5 \\ 0 & 1 & 2 & | & 4 \\ 0 & 0 & \lambda - 5 & | & \mu - 13 \end{bmatrix}

For the system of linear equations to have infinitely many solutions, the rank of the coefficient matrix AA must be equal to the rank of the augmented matrix [AB][A | B], and both must be less than the number of variables (which is 3).

This requires the third row of the augmented matrix to be completely zero:

λ5=0    λ=5\lambda - 5 = 0 \implies \lambda = 5 μ13=0    μ=13\mu - 13 = 0 \implies \mu = 13

Now, calculating the value of λ+μ\lambda + \mu:

λ+μ=5+13=18\lambda + \mu = 5 + 13 = 18

Hence, the correct option is B.

Infinitely Many Solutions of Linear Equations System | Mathematics PYQ Solution - JEE Challenger