JEE Challenger
More from Equilibrium

Identification of Buffer Pair Solutions Upon Mixing

Aqueous solutions of HNO3\text{HNO}_3, KOH\text{KOH}, CH3COOH\text{CH}_3\text{COOH}, and CH3COONa\text{CH}_3\text{COONa} of identical concentrations are provided. The pair(s) of solutions which form a buffer upon mixing is(are)

Options

A

HNO3\text{HNO}_3 and CH3COOH\text{CH}_3\text{COOH}

B

KOH\text{KOH} and CH3COONa\text{CH}_3\text{COONa}

C

HNO3\text{HNO}_3 and CH3COONa\text{CH}_3\text{COONa}

Correct
D

CH3COOH\text{CH}_3\text{COOH} and CH3COONa\text{CH}_3\text{COONa}

Correct

Step-by-Step Solution

An acidic buffer solution typically consists of a weak acid and its conjugate base (a salt of the weak acid with a strong base).

Let the molar concentration of all the provided solutions be CC.


Analysis of the Options:

  1. Option A: HNO3\text{HNO}_3 and CH3COOH\text{CH}_3\text{COOH}

    • HNO3\text{HNO}_3 is a strong acid and CH3COOH\text{CH}_3\text{COOH} is a weak acid.
    • A mixture of a strong acid and a weak acid does not contain a conjugate acid-base pair. Therefore, it cannot act as a buffer solution.
  2. Option B: KOH\text{KOH} and CH3COONa\text{CH}_3\text{COONa}

    • KOH\text{KOH} is a strong base and CH3COONa\text{CH}_3\text{COONa} is a salt of a weak acid and a strong base.
    • Mixing a strong base with a salt does not generate any weak acid or conjugate pair. Hence, it cannot form a buffer solution.
  3. Option C: HNO3\text{HNO}_3 and CH3COONa\text{CH}_3\text{COONa}

    • When a strong acid (HNO3\text{HNO}_3) is added to the salt of a weak acid (CH3COONa\text{CH}_3\text{COONa}), a neutralization reaction occurs:
      CH3COONa (aq)+HNO3 (aq)→CH3COOH (aq)+NaNO3 (aq)\text{CH}_3\text{COONa (aq)} + \text{HNO}_3\text{ (aq)} \rightarrow \text{CH}_3\text{COOH (aq)} + \text{NaNO}_3\text{ (aq)}
    • If the volume of CH3COONa\text{CH}_3\text{COONa} solution (V1V_1) is greater than the volume of HNO3\text{HNO}_3 solution (V2V_2), i.e., V1>V2V_1 > V_2:
      • Initial moles: n(CH3COONa)=C⋅V1n(\text{CH}_3\text{COONa}) = C \cdot V_1 and n(HNO3)=C⋅V2n(\text{HNO}_3) = C \cdot V_2.
      • After reaction, moles remaining:
        Moles of CH3COOH formed=C⋅V2\text{Moles of } \text{CH}_3\text{COOH formed} = C \cdot V_2
        Moles of CH3COONa remaining=C⋅(V1−V2)>0\text{Moles of } \text{CH}_3\text{COONa remaining} = C \cdot (V_1 - V_2) > 0
        Moles of HNO3 remaining=0\text{Moles of } \text{HNO}_3 \text{ remaining} = 0
    • The resulting mixture contains both CH3COOH\text{CH}_3\text{COOH} (weak acid) and CH3COONa\text{CH}_3\text{COONa} (its conjugate base), which forms an acidic buffer solution.
  4. Option D: CH3COOH\text{CH}_3\text{COOH} and CH3COONa\text{CH}_3\text{COONa}

    • CH3COOH\text{CH}_3\text{COOH} is a weak acid and CH3COONa\text{CH}_3\text{COONa} is its salt containing the conjugate base CH3COO−\text{CH}_3\text{COO}^-.
    • Mixing these two solutions directly yields a solution containing a weak acid and its salt, which forms an acidic buffer solution for any non-zero mixing ratio.

Conclusion:

The pair(s) of solutions that can form a buffer upon mixing are C and D.