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Find Value of Parameter given Mean Median and Mean Deviation

Suppose that the mean and median of the non-negative numbers 21,8,17,a,51,103,b,13,67,(a>b)21, 8, 17, a, 51, 103, b, 13, 67, (a > b), are 4040 and 2121, respectively. If the mean deviation about the median is 2626, then 2a2a is equal to:

Options

A

109

B

117

C

161

D

131

Correct

Topics & Concepts

Step-by-Step Solution

To find the value of 2a2a, we follow these steps:

Step 1: Calculate the sum of the numbers using the mean The given set consists of 99 non-negative numbers: 21,8,17,a,51,103,b,13,6721, 8, 17, a, 51, 103, b, 13, 67. Given that the mean of these 99 numbers is 4040: Mean=21+8+17+a+51+103+b+13+679=40\text{Mean} = \frac{21 + 8 + 17 + a + 51 + 103 + b + 13 + 67}{9} = 40

280+a+b9=40\frac{280 + a + b}{9} = 40 280+a+b=360280 + a + b = 360 a+b=80— (Equation 1)a + b = 80 \quad \text{--- (Equation 1)}

Step 2: Use the median property to establish bounds on aa and bb Since there are N=9N = 9 observations, the median is the (9+12)th=5th\left(\frac{9+1}{2}\right)^{\text{th}} = 5^{\text{th}} observation when arranged in ascending order. The 77 known numbers in ascending order are: 8,13,17,21,51,67,1038, 13, 17, 21, 51, 67, 103.

Given that the median is 2121 and a>ba > b, bb must lie to the left of or equal to 2121 (b21b \le 21), and aa must lie to the right of or equal to 2121 (a21a \ge 21) so that 2121 remains the 5th5^{\text{th}} observation.

Step 3: Calculate the mean deviation about the median The mean deviation about the median is given as 2626: Mean Deviation=19i=19xiMedian=26\text{Mean Deviation} = \frac{1}{9} \sum_{i=1}^{9} |x_i - \text{Median}| = 26 i=19xi21=26×9=234\sum_{i=1}^{9} |x_i - 21| = 26 \times 9 = 234

Now, calculating the sum of absolute deviations for the 77 known values: 821+1321+1721+2121+5121+6721+10321|8 - 21| + |13 - 21| + |17 - 21| + |21 - 21| + |51 - 21| + |67 - 21| + |103 - 21| =13+8+4+0+30+46+82=183= 13 + 8 + 4 + 0 + 30 + 46 + 82 = 183

Including aa and bb in the sum of absolute deviations: 183+a21+b21=234183 + |a - 21| + |b - 21| = 234 a21+b21=51|a - 21| + |b - 21| = 51

Since a21a \ge 21 and b21b \le 21, we have a21=a21|a - 21| = a - 21 and b21=21b|b - 21| = 21 - b: (a21)+(21b)=51(a - 21) + (21 - b) = 51 ab=51— (Equation 2)a - b = 51 \quad \text{--- (Equation 2)}

Step 4: Solve for 2a2a Adding Equation (1) and Equation (2): (a+b)+(ab)=80+51(a + b) + (a - b) = 80 + 51 2a=1312a = 131

Thus, 2a2a is equal to 131.

Find Value of Parameter given Mean Median and Mean Deviation | Mathematics PYQ Solution - JEE Challenger