JEE Challenger
More from Differential Equations

Family of Circles Governed by First-Order Differential Equation

The differential equation dydx=1−y2y\frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{y} determines a family of circles with

Options

A

variable radii and a fixed centre at (0,1)(0, 1)

B

variable radii and a fixed centre at (0,−1)(0, -1)

C

fixed radius 1 and variable centres along the xx-axis

Correct
D

fixed radius 1 and variable centres along the yy-axis

Step-by-Step Solution

Separating variables in dydx=1−y2y\frac{dy}{dx} = \frac{\sqrt{1 - y^2}}{y}:
y1−y2 dy=dx\frac{y}{\sqrt{1 - y^2}}\,dy = dx

Integrating both sides:
∫y1−y2 dy=∫dx\int \frac{y}{\sqrt{1 - y^2}}\,dy = \int dx

Let u=1−y2u = 1 - y^2, then du=−2y dy  ⟹  y dy=−du2du = -2y\,dy \implies y\,dy = -\frac{du}{2}:
−12∫u−1/2 du=x+C1  ⟹  −1−y2=x−c-\frac{1}{2}\int u^{-1/2}\,du = x + C_1 \implies -\sqrt{1 - y^2} = x - c
1−y2=−(x−c)\sqrt{1 - y^2} = -(x - c)

Squaring both sides:
1−y2=(x−c)2  ⟹  (x−c)2+y2=11 - y^2 = (x - c)^2 \implies (x - c)^2 + y^2 = 1

This represents a family of circles with fixed radius r=1r = 1 and variable centres (c,0)(c, 0) along the xx-axis.

Correct Answer: C