Evaluation of Ionization Enthalpy Trends in Boron and Carbon Group Elements
Given below are two statements :
Statement I : The second ionization enthalpy of and is in the order of .
Statement II : The correct order in terms of first ionization enthalpy is .
In the light of the above statements, choose the correct answer from the options given below :
Options
Both Statement I and Statement II are true
Both Statement I and Statement II are false
Statement I is true but Statement II is false
Statement I is false but Statement II is true
Topics & Concepts
Step-by-Step Solution
To determine the correctness of the two statements, let us analyze each statement individually:
Analysis of Statement I:
The second ionization enthalpy () corresponds to the removal of a second electron from the unipositive ion ():
- : Electronic configuration is .
- : Electronic configuration is .
- : Electronic configuration is .
Due to the poor shielding provided by the filled -orbitals in , the effective nuclear charge () acting on the outer -electrons increases significantly (d-block contraction). As a result, it requires more energy to remove an electron from than from .
The experimental values for the second ionization enthalpies () are:
Thus, the correct order of second ionization enthalpy is:
Therefore, Statement I is false.
Analysis of Statement II:
For Group 14 elements (), the experimental values for the first ionization enthalpy () are:
The general trend decreases down the group from to , with a small increase at due to poor shielding by electrons (lanthanoid contraction).
Thus, the correct increasing order of first ionization enthalpy is:
Statement II states the order as , which is completely opposite to the actual trend.
Therefore, Statement II is false.
Conclusion:
Since both Statement I and Statement II are false, the correct option is B.