JEE Challenger
More from p-Block Elements

Evaluation of Ionization Enthalpy Trends in Boron and Carbon Group Elements

Given below are two statements :

Statement I : The second ionization enthalpy of B,Al\text{B}, \text{Al} and Ga\text{Ga} is in the order of B>Al>Ga\text{B} > \text{Al} > \text{Ga}.

Statement II : The correct order in terms of first ionization enthalpy is Si<Ge<Pb<Sn\text{Si} < \text{Ge} < \text{Pb} < \text{Sn}.

In the light of the above statements, choose the correct answer from the options given below :

Options

A

Both Statement I and Statement II are true

B

Both Statement I and Statement II are false

Correct
C

Statement I is true but Statement II is false

D

Statement I is false but Statement II is true

Topics & Concepts

Step-by-Step Solution

To determine the correctness of the two statements, let us analyze each statement individually:

Analysis of Statement I:

The second ionization enthalpy (ΔiH2\Delta_i H_2) corresponds to the removal of a second electron from the unipositive ion (M+M^+):

  1. B+\text{B}^+: Electronic configuration is [He]2s2[\text{He}] 2s^2.
  2. Al+\text{Al}^+: Electronic configuration is [Ne]3s2[\text{Ne}] 3s^2.
  3. Ga+\text{Ga}^+: Electronic configuration is [Ar]3d104s2[\text{Ar}] 3d^{10} 4s^2.

Due to the poor shielding provided by the filled 3d3d-orbitals in Ga+\text{Ga}^+, the effective nuclear charge (ZeffZ_{\text{eff}}) acting on the outer 4s4s-electrons increases significantly (d-block contraction). As a result, it requires more energy to remove an electron from Ga+\text{Ga}^+ than from Al+\text{Al}^+.

The experimental values for the second ionization enthalpies (ΔiH2\Delta_i H_2) are:

  • B2427 kJ mol1\text{B} \approx 2427 \text{ kJ mol}^{-1}
  • Al1816 kJ mol1\text{Al} \approx 1816 \text{ kJ mol}^{-1}
  • Ga1979 kJ mol1\text{Ga} \approx 1979 \text{ kJ mol}^{-1}

Thus, the correct order of second ionization enthalpy is: B>Ga>Al\text{B} > \text{Ga} > \text{Al}

Therefore, Statement I is false.


Analysis of Statement II:

For Group 14 elements (C,Si,Ge,Sn,Pb\text{C}, \text{Si}, \text{Ge}, \text{Sn}, \text{Pb}), the experimental values for the first ionization enthalpy (ΔiH1\Delta_i H_1) are:

  • Si786 kJ mol1\text{Si} \approx 786 \text{ kJ mol}^{-1}
  • Ge761 kJ mol1\text{Ge} \approx 761 \text{ kJ mol}^{-1}
  • Sn708 kJ mol1\text{Sn} \approx 708 \text{ kJ mol}^{-1}
  • Pb715 kJ mol1\text{Pb} \approx 715 \text{ kJ mol}^{-1}

The general trend decreases down the group from C\text{C} to Sn\text{Sn}, with a small increase at Pb\text{Pb} due to poor shielding by 4f4f electrons (lanthanoid contraction).

Thus, the correct increasing order of first ionization enthalpy is: Sn<Pb<Ge<Si\text{Sn} < \text{Pb} < \text{Ge} < \text{Si}

Statement II states the order as Si<Ge<Pb<Sn\text{Si} < \text{Ge} < \text{Pb} < \text{Sn}, which is completely opposite to the actual trend.

Therefore, Statement II is false.


Conclusion:

Since both Statement I and Statement II are false, the correct option is B.

Evaluation of Ionization Enthalpy Trends in Boron and Carbon Group Elements | Chemistry PYQ Solution - JEE Challenger