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Evaluate Principal Value of Composite Inverse Trigonometric Expression

Considering only the principal values of the inverse trigonometric functions, the value of cot1(cot(11))+10sin(2cos1(12))+10sin(2tan1(2))\cot^{-1}(\cot(-11)) + 10 \sin\left(2 \cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right) + 10 \sin(2 \tan^{-1}(2)) is

Options

A

3π+73\pi + 7

B

77

C

4π+74\pi + 7

Correct
D

3π53\pi - 5

Step-by-Step Solution

To evaluate the given expression: E=cot1(cot(11))+10sin(2cos1(12))+10sin(2tan1(2))E = \cot^{-1}(\cot(-11)) + 10 \sin\left(2 \cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right) + 10 \sin(2 \tan^{-1}(2))

We evaluate each term individually using the principal values of the inverse trigonometric functions:

  1. For the first term, since 4π11(0,π)4\pi - 11 \in (0, \pi) and cot(4π11)=cot(11)\cot(4\pi - 11) = \cot(-11), we have: cot1(cot(11))=4π11\cot^{-1}(\cot(-11)) = 4\pi - 11

  2. For the second term, using cos1(12)=π4\cos^{-1}\left(\frac{1}{\sqrt{2}}\right) = \frac{\pi}{4}: 10sin(2π4)=10sin(π2)=1010 \sin\left(2 \cdot \frac{\pi}{4}\right) = 10 \sin\left(\frac{\pi}{2}\right) = 10

  3. For the third term, using the identity sin(2tan1x)=2x1+x2\sin(2\tan^{-1} x) = \frac{2x}{1+x^2} with x=2x=2: 10sin(2tan1(2))=102(2)1+22=1045=810 \sin(2 \tan^{-1}(2)) = 10 \cdot \frac{2(2)}{1 + 2^2} = 10 \cdot \frac{4}{5} = 8

Summing the results from all three terms yields: E=(4π11)+10+8=4π+7E = (4\pi - 11) + 10 + 8 = 4\pi + 7

Thus, the correct option is (C).

Evaluate Principal Value of Composite Inverse Trigonometric Expression | Mathematics PYQ Solution - JEE Challenger