JEE Challenger
More from Matrices

Evaluate Expression Involving Elements of Matrix Difference

Let A=[100310931]A = \begin{bmatrix} 1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1 \end{bmatrix} and B=[bij],1i,j3B = [b_{ij}], 1 \le i, j \le 3. If B=A99IB = A^{99} - I, then the value of b31b21b32\frac{b_{31} - b_{21}}{b_{32}} is :

Options

A

99

B

199

C

149

Correct
D

159

Topics & Concepts

MatricesMatrices

Step-by-Step Solution

To find the value of b31b21b32\frac{b_{31} - b_{21}}{b_{32}}, we decompose matrix AA as A=I+NA = I + N, where N=[000300930]N = \begin{bmatrix} 0 & 0 & 0 \\ 3 & 0 & 0 \\ 9 & 3 & 0 \end{bmatrix} is a nilpotent matrix satisfying N3=0N^3 = 0.

By binomial expansion, A99=(I+N)99=I+99N+99×982N2A^{99} = (I + N)^{99} = I + 99N + \frac{99 \times 98}{2}N^2, which simplifies B=A99IB = A^{99} - I to B=99N+4851N2B = 99N + 4851N^2.

Evaluating the matrix elements yields: b21=99×3=297b_{21} = 99 \times 3 = 297 b32=99×3=297b_{32} = 99 \times 3 = 297 b31=99×9+4851×9=44550b_{31} = 99 \times 9 + 4851 \times 9 = 44550

Substituting these into the given expression gives: b31b21b32=44550297297=44253297=149\frac{b_{31} - b_{21}}{b_{32}} = \frac{44550 - 297}{297} = \frac{44253}{297} = 149

Hence, the correct option is C.

Evaluate Expression Involving Elements of Matrix Difference | Mathematics PYQ Solution - JEE Challenger