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ChemMedMain 2026 • 4th Apr - Shift 2

Estimation of Percentage of Sulphur in Organic Compound

In sulphur estimation, 2.0×10−3 mol2.0 \times 10^{-3}\text{ mol} of an organic compound (X) (molar mass 76 g mol−176\text{ g mol}^{-1}) gave 0.4813 g0.4813\text{ g} of barium sulphate (molar mass 233 g mol−1233\text{ g mol}^{-1}). The percentage of sulphur in the compound (X) is ______ ×10−1%\times 10^{-1}\% (Nearest integer)

Official Numerical Answer435

Topics & Concepts

Organic Chemistry - Basic PrinciplesMole ConceptStoichiometry

Step-by-Step Solution

To determine the percentage of sulphur in the organic compound (X)(X), we follow these steps:

Step 1: Calculate the mass of the organic compound (X)(X) Given:

  • Moles of organic compound (X)=2.0×10−3 mol(X) = 2.0 \times 10^{-3} \text{ mol}
  • Molar mass of organic compound (X)=76 g mol−1(X) = 76 \text{ g mol}^{-1}

Mass of compound (X)=Moles×Molar mass\text{Mass of compound } (X) = \text{Moles} \times \text{Molar mass} Mass of compound (X)=2.0×10−3 mol×76 g mol−1=0.152 g\text{Mass of compound } (X) = 2.0 \times 10^{-3} \text{ mol} \times 76 \text{ g mol}^{-1} = 0.152 \text{ g}

Step 2: Calculate the mass of sulphur present in the formed barium sulphate (BaSO4\text{BaSO}_4) Given:

  • Mass of BaSO4=0.4813 g\text{BaSO}_4 = 0.4813 \text{ g}
  • Molar mass of BaSO4=233 g mol−1\text{BaSO}_4 = 233 \text{ g mol}^{-1}
  • Molar mass of Sulphur (SS) = 32 g mol−132 \text{ g mol}^{-1}

Mass of Sulphur=Molar mass of SMolar mass of BaSO4×Mass of BaSO4\text{Mass of Sulphur} = \frac{\text{Molar mass of } S}{\text{Molar mass of } \text{BaSO}_4} \times \text{Mass of } \text{BaSO}_4 Mass of Sulphur=32233×0.4813 g≈0.0661 g\text{Mass of Sulphur} = \frac{32}{233} \times 0.4813 \text{ g} \approx 0.0661 \text{ g}

Step 3: Calculate the percentage of sulphur in the organic compound Percentage of Sulphur=(Mass of SulphurMass of organic compound)×100\text{Percentage of Sulphur} = \left( \frac{\text{Mass of Sulphur}}{\text{Mass of organic compound}} \right) \times 100 Percentage of Sulphur=(0.06610130.152)×100≈43.4877%\text{Percentage of Sulphur} = \left( \frac{0.0661013}{0.152} \right) \times 100 \approx 43.4877\%

Step 4: Convert to the required format The question asks for the answer in the form of ______ ×10−1%\times 10^{-1}\%: 43.4877%=434.877×10−1%43.4877\% = 434.877 \times 10^{-1}\%

Rounding off to the nearest integer, we get 435435.

Estimation of Percentage of Sulphur in Organic Compound | Chemistry PYQ Solution - JEE Challenger